CODEWITHSUNDEEP
c++listsortingstruct
Miguel Ribeiro
Miguel Ribeiro

Reputation: 1

Sorting a struct list of struct

I have two structs:

struct memBlock {
    uint32_t  pid;
    uint32_t  moduleSize;
    void*  moduleStart;
};

struct memory{
    uint32_t  memSize;
    uint32_t  memSizeOS;
    uint32_t  chunkSize;
    uint32_t  nextFit;
    list<memBlock> freeMem;
    list<memBlock> usedMem;
};

memory memo;

I want to sort the freeMem list of memo in ascending order of moduleSize.

How can I accomplish this?

I tried this:

sort( memo.freeMem.begin( ), memo.freeMem.end( ), 
                []( const memory& a, const memory&b ){
                return a.freeMem < b.freeMem;
            } );

but I don't know how to specify that sort should consider moduleSize variable.

Solution:

memo.freeMem.sort([]( memBlock a,memBlock b){return a.moduleSize<b.moduleSize;});

Upvotes: 0

Views: 60

Answers (1)

Jeremy Friesner
Jeremy Friesner

Reputation: 73081

Probably you want something like this:

sort( memo.freeMem.begin( ), memo.freeMem.end( ), 
   []( const memblock& a, const memblock&b ){
   return a.moduleSize < b.moduleSize;
} );

Upvotes: 3

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