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Ordnael
Ordnael

Reputation: 31

How to receive URL File as parameter and save it to disk using FastAPI?

I would like to know if there is a way for FastAPI to receive a URL of a file as a parameter and save this file to disk? I know it is possible with the requests library using requests.get() method, but is it possible with FastAPI to receive the URL and save it directly?

I tried using file: UploadFile = File(...), but then it doesn't download the file when the URL is sent.

Upvotes: 1

Views: 348

Answers (1)

Adam Huganir
Adam Huganir

Reputation: 11

I don't believe so. I've come across this before and was unable to find a solution (and ended up using requests like you mentioned), but seeing this I wanted to check again more thoroughly.

Reviewing the uvicorn and fastapi repositories by searching the code itself, I see no functions/code that reference requests or urllib (they do use urllib.parse/quote, etc though) that would be 2 likely suspects to build requests. They do use httpx.AsyncClient, but only in tests. I would expect to see some use of these libraries in the main uvicorn/fastapi libraries if they had code to make external requests.

Seeing the above, I actually think I will change my code to use httpx.AsyncClient anyways since it is already a dependency.

Upvotes: 1

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