What is wrong f-string in Python?

Question

• below code is my valid requirement.

import numpy as np
a =np.array([1, 3, 0, 2], int)
b =np.array([5, 2, 1, 2], int)
print(f'{a > b = }')

• result is ok

a > b = array([False,  True, False, False])

---

• I wanna make inner function which have f-string style.

import numpy as np
a =np.array([1, 3, 0, 2], int)
b =np.array([5, 2, 1, 2], int)

def myprn(text):
    print(f'{text = }')

myprn(a > b)

• result is not my requirement
• I wanna print 'a > b' instead of 'text'

text = array([False,  True, False, False])
#^^^ how to fix this requirement?

Answer 1

Thanks to @Tomerikoo.

• His reply gave me a hint. I was able to learn the movements I wanted according to his comments

@Tomerikoo's comment

The only way I can think to make something similar to this work is print(f'{text} = {eval(text)}') and then passing the function strings with the expression, i.e. myprn('a > b')

Answer 2

You can't, = in f-string is self-documenting sign which just prints expression before it as is. Doc reference