CODEWITHSUNDEEP
javascriptreactjsreact-nativefrontendpopupwindow
Abcd Efgh
Abcd Efgh

Reputation: 57

Auto open new tab when page is loaded in react

I have a requirement to be implemented where- when the form is loaded, basis one of the attribute which contains a url link - a new browser tab should be auto opened with that url when form is loaded.

So i checked few stakc overflow links and found one solution Maintaining href "open in new tab" with an onClick handler in React

      const openInNewTab = (url) => {
        const newWindow = window.open(url, '_blank', 'noopener,noreferrer')
        if (newWindow) newWindow.opener = null
      }


       return (
            <ul>
            {dataset.map((x, id) => (
                <li 
                key={id}
                >
                    <b>{x.split('~')[0]}</b>&ensp;-&ensp;{checkString(x.split('~')[1])}
                    {x.split('~')[0]==='PAGE_URL'  ?  
                        openInNewTab(x.split('~')[1])
                    :
                    <></>
                }
                </li>
               
            ))}
            </ul>
        );

So with above code, when my form is loaded, it immediately loads new tab on broswer as expected but the issue here is whenever i try to type in other form questions or click on any button like radio button on that form, everytime it is opening new tab which i don't want. How do i prevent multiple times auto pop up of new tab or is there any other solution? Please help with solution or alternatives.

I mentioned whever i tried in above

Upvotes: 0

Views: 1043

Answers (1)

Ghouse Mohamed
Ghouse Mohamed

Reputation: 437

You can call the openInNewTab function from a useEffect hook. The reason a new tab is opened when ever you type in something in the input field is because react is re-rendering that component due to state changes. Since you want this function to be called only once, you can move the logic of calling this function to a useEffect hook.

Upvotes: 0

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