CODEWITHSUNDEEP
pythondjangodjango-viewsdjango-urlspython-class
samitugal
samitugal

Reputation: 3

AttributeError at type object 'Services' has no attribute 'app'

I newly started to develop Django. I want to connect my python algorithm and Django web ui so I tried to connect both of them in views.py but I encountered a problem.

It says AttributeError at type object 'Services' has no attribute 'app' but I declared it in the queryOnMetadataModel.init. I don't know what is wrong. Could someone help me?

These are my code snippets;

from Neo4jConnection import App   
import json

class Services:
    def __init__(self):
        uri = "neo4j+s://a50f760a.databases.neo4j.io:7687"
        user = "neo4j"
        password = "password"
        self.app = App(uri, user, password)
    
    def find_node_type(self,nodeName):
        node_type = self.app.find_node_type(nodeName)
        self.app.close()
        return node_type

from django.shortcuts import render
from BitirmeTeziSourceCode.queryOnMetadataModel import Services

import sys
sys.path.append(".")

# Create your views here.

def home(request):

    data = Services.find_node_type(Services , 'Region')
    
    nodes = {
        "nodes" : data
    }
    
    return render(request , "index.html" , nodes)

urls.py


from django.urls import path
from . import views

urlpatterns = [
    path("" , views.home)
]

Error Image

I want to access output of Services.find_node_type(Services , 'Region') from index.html

Upvotes: 0

Views: 699

Answers (1)

Sunderam Dubey
Sunderam Dubey

Reputation: 8837

You need to make instance first instead of directly using class so:

def home(request):
    instance=Services()
    data = instance.find_node_type('Region')
    
    nodes = {
        "nodes" : data
    }
    
    return render(request , "index.html" , nodes)

Note: Also it is better to write classes in singular case so it is better to write Service not Services.

Upvotes: 1

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