Reputation: 3021
I'm looking for a regex pattern that will look for an attribute within an HTML tag. Specifically, I'd like to find all instances of ...
style=""
... and remove it from the HTML tag that it is contained within. Obviously this would include anything contained with the double quotes as well.
I'm using Classic ASP to do this. I already have a function setup for a different regex pattern that looks for all HTML tags in a string and removes them. It works great. But now I just need another pattern for specifically removing all of the style attributes.
Any help would be greatly appreciated.
Upvotes: 18
Views: 40734
Reputation: 1964
In visual studio find and replace, this is what i do to remove style and class attributes:
\s*style|class="[^"]*\n*"
This removes the beginning spaces and style and class attributes. It looks for anything except a double quote in these attributes and then newline(s), in case if it spreads out to new lines, and lastly adds the closing double quote
Upvotes: 4
Reputation: 5905
The following expression should remove anything within a style
attribute (including the attribute itself); crucially this includes whether the attribute uses double or single quotes:
/style=("|')(?:[^\1\\]|\\.)+?\1/gi
This splits the capture groups so that they can match on single or double-quotes, and then capture anything in between, including URL-encoded characters & line breaks, whilst leaving other attributes (like classes or names) intact.
Tested here: https://regexr.com/4rovf
Upvotes: 0
Reputation: 727
Try this, it will replace style attribute and it's value completely
const regex = /style="(.*?)"/gm;
const str = `<div class="frame" style="font-family: Monaco, Consolas, "Courier New", monospace; font-size: 12px; background-color: rgb(245, 245, 245);">some text</div>`;
const subst = ``;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Upvotes: 5
Reputation: 11
I tried Jason Gennaro's regular expression and slightly modified it
/style="[a-zA-Z0-9:;&\."\s\(\)\-\,]*|\\/ig
This regular expression captures some specific cases with "
inside the string for example
<div class="frame" style="font-family: Monaco, Consolas, "Courier New", monospace; font-size: 12px; background-color: rgb(245, 245, 245);">some text</div>
Upvotes: 1
Reputation: 6989
Perhaps a simpler expression is
style="[^\"]*"
so everything between the double quotes except a double quote.
Upvotes: 54
Reputation: 34855
I think this might do it:
/style="[a-zA-Z0-9:;\.\s\(\)\-\,]*"/gi
You could also put these in capturing groups, if you wanted to replace some parts only
/(style=")([a-zA-Z0-9:;\.\s\(\)\-\,]*)(")/gi
Working Example: http://regexr.com?2up30
Upvotes: 25
Reputation: 26930
This works with perl. Maybe you need to change the regex to match ASP rules a little bit but it should work for any tag.
$file=~ s/(<\s*[a-z][a-z0-9]*.*\s)(style\s*=\s*".*?")([^<>]*>)/$1 $3/sig;
Where line is an html file.
Also this is in .net C#
string resultString = null;
string subjectString = "<html style=\"something\"> ";
resultString = Regex.Replace(subjectString, @"(<\s*[a-z][a-z0-9]*.*\s)(style\s*=\s*"".*?"")([^<>]*>)", "$1 $3", RegexOptions.Singleline | RegexOptions.IgnoreCase);
Result : <html >
Upvotes: 0