CODEWITHSUNDEEP
python-3.x
Lourna
Lourna

Reputation: 13

is there a way to make an array of words in python?

i am a beginner in python my wish is to make an array of n lines and n rows. I have a dictionnary of words and i need to put them in an array n*n . provisions ={'cake':'20','eggs':'10','tomatoes':'4','potatoes':'2','bread':'4'}

| /  | 1           | 2            |
| 1  | cake        | eggs         |
| 2  | tomatoes    | potatoes     |

that is an example of what i want. we have here an array of 2 lines and 2 rows. i can have a dictionnary of more than 5 elements.That is just for an example.

import string

provisions = {'cake':'20','eggs':'10','tomatoes':'4','potatoes':'2','bread':'3'} 
tab = []

#i can modify the n for having an array of n*n no matter if provisions has more elements

n = 2
j = 0
i = 0

if provisions:
    for k,v in provisions.items():
        while i<n:
            while j<n:
                print(f"{k}")
                tab[[i],[j]] = provisions[i]
                j += 1
            i += 1

Upvotes: 1

Views: 183

Answers (2)

Lea
Lea

Reputation: 23

if you want more of visibility of the different lists, you can just add that code at the end of the answer above:

for l in tab:
    print(l)

that will give:

['cake' 'eggs']
['tomatoes', 'potatoes']

for facilitate the treatment of the dictionary and having the array that you want, you can take all the keys of your dictionary and stock them in a list:

list = []
if provisions:
    for k, v in provisions.items():
        
        list.append(k)
print(list)

There is a way to put that array (tab) in a csv file.

import math
import xlsxwriter

provisions = {'cake': '20', 'eggs': '10', 'tomatoes': '4', 
'potatoes': '2', 'bread': '3'}
workbook = xlsxwriter.Workbook('tableau.xlsx')
worksheet = workbook.add_worksheet()
n = 2
...
print(tab)
row = 0
col = 0

for module in tab:
    str1 =''.join(module)
    if str1.isupper():
        pass
    else:
        worksheet.write_row(row, col, module)
        row += 1
workbook.close()

And it does the job.But you must to be sure that in choosing n you have enough of data for making n*n.

Upvotes: 0

lin
lin

Reputation: 1589

 You can try the code below.Iterate the dict, count current index (m variable)and compute position in the matrix.

import math

provisions = {'cake': '20', 'eggs': '10', 'tomatoes': '4', 'potatoes': '2', 'bread': '3'}

n = 2
# init matrix
tab = [[0 for x in range(n)] for y in range(n)]

# I can modify the n for having an array of n*n no
# matter if provisions has more elements

# index in the dict
m = 0
if provisions:
    for k, v in provisions.items():
        # prevent index overflow
        if m < n * n:
            # compute position in matrix
            tab[math.floor(m / n)][m % n] = k
            m = m + 1

print(tab)

 If you want to determine element for position tab[i][j],you first get the index of this element : i * n + j(the first element in the dict is 0).Unfortunately, there is still no dedicated method to index into keys() / values() of the dictionary, you can find something in this answer.

Upvotes: 1

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