CODEWITHSUNDEEP
c#.netstring
Sriwantha Attanayake
Sriwantha Attanayake

Reputation: 7908

Parametrizing string in .NET C#

How to replace a method signature to accept parameterized strings without using param keywords. I have seen this functionality in Console.WriteLine(). e.g. 

public void LogErrors(string message, params string[] parameters) { }

Scenario:

I have an error login function called 

LogErrors(string message)
{
    //some code to log errors
}

I am calling this function at different locations in the program in a way that the error messages are hardcoded. e.g.:

LogError("Line number " + lineNumber + " has some invalid text");

I am going to move these error messages to a resource file since I might change the language (localization) of the program later. In that case, how can I program to accept curly bracket bases parameterized strings? e.g.:

LogError("Line number {0} has some invalid text", lineNumber)

will be written as:

LogError(Resources.Error1000, lineNumber)

where Error1000 will be "Line number {0} has some invalid text"

Upvotes: 4

Views: 1230

Answers (3)

sll
sll

Reputation: 62504

Basically use String.Format() method:

public void LogError(string format, params string[] errorMessages)
{
   log.WriteError(String.Format(
                          CultureInfo.InvariantCulture, 
                          format, 
                          errorMessages));
}

Upvotes: 2

Jon Skeet
Jon Skeet

Reputation: 1500665

You probably want two methods:

public void LogErrors(string message, params string[] parameters)
{
    LogErrors(string.Format(message, parameters));
}

public void LogErrors(string message)
{
    // Use methods with *no* formatting
}

I wouldn't just use a single method with the params, as then it'll try to apply formatting even if you don't have any parameters, which can make things harder when you want to use "{" and "}" within a simple message without any parameters.

Upvotes: 7

SLaks
SLaks

Reputation: 887449

Just call String.Format in your function:

string output = String.Format(message, parameters);

Upvotes: 12

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