Reputation: 31
I'd like to instantiate instances of a generic type and pass them around as if they were generic objects of an interface that they implement, such as below. Clearly, this is not allowed. Why is this, and what is the general practice for handling such situations? thanks.
public class MyType<T> where T : IComparable { }
MyType<IComparable> things = new MyType<Int32>();
this gets error:
Cannot implicitly convert type MyType<Int32> to MyType<IComparable>
I want to do this because I need different types of things
that I want to pass around to more generic methods such as
public void DoSomething(MyType<IComparable> things) {...}
Upvotes: 2
Views: 116
Reputation: 112324
The assignment compatibility of generic type arguments does not make the generic type itself assignment compatible. This is why: Let's assume that we declared the generic class like this:
public class MyType<T> where T : IComparable
{
public T Value { get; set; }
}
And let's assume that this would compile ...
var intObject = new MyType<int> { Value = 42 };
MyType<IComparable> things = intObject; // Does not compile!
... then we could write
// things.Value has the static type IComparable
things.Value = "hello"; // Allowed because string is IComparable
But this is not possible since the underlying object is a MyType<int>
and thus its Value
property has the type int
. Therefore, we are not allowed to substitute a MyType<int>
for a MyType<IComparable>
.
Upvotes: 2