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t-sqlselectsplit
SpoiledTechie.com
SpoiledTechie.com

Reputation: 10725

Implementing and applying a string split in T-SQL

I have this statement in T-SQL.

SELECT Bay From TABLE where uid in (
    select B_Numbers from Info_Step WHERE uid = 'number'
)

I am selecting "multiple" BAYs from TABLE where their uid is equal to a string of numbers like this:

B_Numbers = 1:45:34:98

Therefore, I should be selecting 4 different BAYs from TABLE. I basically need to split the string 1:45:34:98 up into 4 different numbers.

I'm thinking that Split() would work, but it doesn't and I get a syntax error. Any thoughts from the T-SQL gods would be awesome!

Upvotes: 0

Views: 2608

Answers (5)

priyanka.sarkar
priyanka.sarkar

Reputation: 26518

You can even try this

declare @str varchar(50)
set @str = '1:45:34:98'

;with numcte as(
select 1 as rn union all select rn+1 from numcte where rn<LEN(@str)),
getchars as(select 
ROW_NUMBER() over(order by rn) slno,
rn,chars from numcte 
cross apply(select SUBSTRING(@str,rn,1) chars)X where chars = ':') 

select top 1 
    Bay1 = SUBSTRING(@str,0,(select rn from getchars where slno = 1)) 
    ,Bay2 = SUBSTRING(@str,
            (select rn from getchars where slno = 1) + 1,
            (((select rn from getchars where slno = 2)-
            (select rn from getchars where slno = 1)
            )-1))
    ,Bay3 = SUBSTRING(@str,
            (select rn from getchars where slno = 2) + 1,
            (((select rn from getchars where slno = 3)-
            (select rn from getchars where slno = 2)
            )-1))
    ,Bay4 = SUBSTRING(@str,
            (select rn from getchars where slno = 3)+1,
            LEN(@str))
    from getchars

Output:

Bay1    Bay2    Bay3    Bay4
1   45  34  98

Upvotes: 0

beach
beach

Reputation: 8640

Here is a method that uses an auxiliary numbers table to parse the input string. The logic can easily be added to a function that returns a table. That table can then be joined to lookup the correct rows.

Step 1: Create the Numbers table

SET NOCOUNT ON
GO

IF EXISTS
(
    SELECT  1
    FROM    INFORMATION_SCHEMA.TABLES
    WHERE       TABLE_NAME  = 'Numbers'
            AND     TABLE_SCHEMA    = 'dbo'
            AND     TABLE_TYPE  = 'BASE TABLE'
)
BEGIN
    DROP TABLE dbo.Numbers
END
GO

CREATE TABLE dbo.Numbers
(
    Number smallint  IDENTITY(1, 1) PRIMARY KEY
)
GO

WHILE 1 = 1
BEGIN
    INSERT INTO dbo.Numbers DEFAULT VALUES

    IF SCOPE_IDENTITY() = 32767 
    BEGIN
        BREAK
    END
END
GO

Step 2: Parse the Input String

CREATE FUNCTION dbo.ParseString(@input_string varchar(8000), @delim varchar(8000) = " ")
RETURNS TABLE
AS RETURN
(
    SELECT Number 
    FROM dbo.Numbers
    WHERE CHARINDEX 
    ( 
        @delim + CONVERT(VARCHAR(12),Number) + @delim, 
        @delim + @input_string + @delim 
    ) > 0 
)
GO

**EXAMPLE**
SELECT * FROM dbo.ParseString('1:45:34:98',':')

Step 3: Use the results however you want/need

Number
------
1
34
45
98

End-To-End Example

Create function that returns the appropriate BNumber (of course change it to use the commented out SQL)

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION dbo.GetBNumber (@uid int)
RETURNS VARCHAR(8000) 
AS
BEGIN
    RETURN '1:45:34:98'
    --select B_Numbers from Info_Step WHERE uid = @uid
END
GO

Use the use functions to return the desired results

-- Using Test Data
SELECT N.Number FROM Numbers N
JOIN dbo.ParseString(dbo.GetBNumber(12345),':') Q ON Q.Number = N.Number

-- Using Your Data (Untested but should work.)
SELECT N.Bay
FROM TABLE N
JOIN dbo.ParseString(dbo.GetBNumber(ENTER YOU NUMBER HERE),':') Q ON Q.Number = N.uid

Results

Number
------
1
34
45
98

Upvotes: 2

Gavin Miller
Gavin Miller

Reputation: 43845

What you can do is loop through the B_Numbers entries and do your own split on : Insert those entries into a temp table and then perform your query. 

DECLARE @i             int
DECLARE @start         int
DECLARE @B_Numbers     nvarchar(20)
DECLARE @temp          table (
    number nvarchar(10)
)

-- SELECT B_Numbers FROM Info_Step WHERE uid = 'number'
SELECT @B_Numbers = '1:45:34:98'

SET @i = 0
SET @start = 0

-- Parse out characters delimited by ":";  
-- Would make a nice user defined function.
WHILE @i < len(@B_Numbers)
BEGIN
    IF substring(@B_Numbers, @i, 1) = ':'
    BEGIN
        INSERT INTO @temp
        VALUES (substring(@B_Numbers, @start, @i - @start))
        SET @start = @i + 1
    END

    SET @i = @i + 1
END

-- Insert last item
INSERT INTO @temp
VALUES (substring(@B_Numbers, @start, @i - @start + 1))

-- Do query with parsed values
SELECT Bay FROM TABLE WHERE uid in (SELECT * FROM @temp)

Upvotes: 0

ScottStonehouse
ScottStonehouse

Reputation: 24965

Here is an implementation of a split function that returns the list of numbers as a table:

http://rbgupta.blogspot.com/2007/03/split-function-tsql.html

Looks like this would set you on your way...

Upvotes: 2

jason saldo
jason saldo

Reputation: 9960

You should keep your arrays as rows but if I understand your question I think this will work.

SELECT 
    Bay 

From 
    TABLE
    join  Info_Step 
    on B_Numbers like '%'+ uid  +'%'

where 
    Info_Step.uid = 'number'

This query will do a full table scan because of the like operator.

Upvotes: 0

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