CODEWITHSUNDEEP
lualua-patterns
Rai
Rai

Reputation: 445

Trying to get some kind of key:value data from a string in Lua

I'm (again) stuck because patterns... so let's see if with a little of help... The case is I have e. g. a string returned by a function that contains the following:

📄 My Script
ScriptID:RL_SimpleTest
Version:0.0.1
ScriptType:MenuScript
AnotherKey:AnotherValue
And, maybe, some more text...

And I'd want to parse it line by line and should the line contains a ":" get the left side content of the line in a variable (k) and the right content in another one (v), so e. g. I'd have k containing "ScriptID" and v containing "RL_SimpleTest" for the second line (the first one should be just ignored) and so on...

Well, I've started with something like this:

function RL_Test:StringToKeyValue(str, sep1, sep2)
    sep1 = sep1 or "\n"
    sep2 = sep2 or ":"
    local t = {}
    for line in string.gmatch(str, "([^" .. sep1 .. "]+)") do
        print(line)
        for k in string.gmatch(line, "([^" .. sep2 .. "]+)") do --Here is where I'm lost trying to get the key/value pair separately and at the same time...
            --t[k] = v
            print(k)
        end
    end
    return t
end

With the hope once I got isolated the line containing the data in the key:value form that I want to extract, I'd be able to do some kind of for k, v in string.gmatch(line, "([^" .. sep2 .. "]+)") or something so and that way get the two pieces of data, but of course it doesn't work and even though I have a feeling it's a triviality I don't know even where to start, always for the lack of patterns understanding...

Well, I hope at least I exposed it right... Thanks in advance for any help.

Upvotes: 0

Views: 426

Answers (2)

Piglet
Piglet

Reputation: 28950

local t = {}
for line in (s..'\n'):gmatch("(.-)\r?\n") do
  for a, b in line:gmatch("([^:]+):([^:\n\r]+)") do
    t[a] = b
  end
end

The pattern is quite simple. Match anything that is not a colon that is followed by a colon that is followed by anything that is not a colon or a line break. Put what you want in captures and you're done.

Upvotes: 2

Luatic
Luatic

Reputation: 11171

I assume every line is of the format k:v, containing exactly one colon, or containing no colon (no k/v pair).

Then you can simply first match nonempty lines using [^\n]+ (assuming UNIX LF line endings), then match each line using ^([^:]+):([^:]+)$. Breakdown of the second pattern:

  • ^ and $ are anchors. They force the pattern to match the entire line.
  • ([^:]+) matches & captures one or more non-semicolon characters.

This leaves you with:

function RL_Test:StringToKeyValue(str)
    local t = {}
    for line in str:gmatch"[^\n]+" do
        local k, v = line:match"^([^:]+):([^:]+)$"
        if k then -- line is k:v pair?
           t[k] = v
        end
    end
    return t
end

If you want to support Windows CRLF line endings, use for line in (s..'\n'):gmatch'(.-)\r?\n' do as in Piglet's answer for matching the lines instead.

This answer differs from Piglet's answer in that it uses match instead of gmatch for matching the k/v pairs, allowing exactly one k/v pair with exactly one colon per line, whereas Piglet's code may extract multiple k/v pairs per line.

Upvotes: 1

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