Reputation: 49
I was trying to write a program which plots level set for any given function.
rmin = -5.0
rmax = 5.0
c = 4.0
x = np.arange(rmin,rmax,0.1)
y = np.arange(rmin,rmax,0.1)
x,y = np.meshgrid(x,y)
f = lambda x,y: y**2.0 - 4*x
realplots = []
for i in range(x.shape[0]):
for j in range(x.shape[1]):
if abs(f(x[i,j],y[i,j])-c)< 1e-4:
realplots.append([x[i,j],y[i,j]])`
But it being a nested for loop, is taking lot of time. Any help in vectorizing the above code/new method of plotting level set is highly appreciated.(Note: The function 'f' will be changed at the time of running.So, the vectorization must be done without considering the function's properties)
I tried vectorizing through
ans = np.where(abs(f(x,y)-c)<1e-4,np.array([x,y]),[0,0])
but it was giving me operands could not be broadcast together with shapes (100,100) (2,100,100) (2,)
I was adding [0,0]
as an escape from else
condition in np.where which is indeed wrong.
Upvotes: 0
Views: 38
Reputation: 3542
Since you get the values rather than the indexes, you don't really need np.where
.
You can directly use the mask to index x
and y
, look at the "Boolean array indexing" section of the documentation.
It is straightforward:
def vectorized(x, y, c, f, threshold):
mask = np.abs(f(x, y) - c) < threshold
x, y = x[mask], y[mask]
return np.stack([x, y], axis=-1)
Your function for reference:
def op(x, y, c, f, threshold):
res = []
for i in range(x.shape[0]):
for j in range(x.shape[1]):
if abs(f(x[i, j], y[i, j]) - c) < threshold:
res.append([x[i, j], y[i, j]])
return res
Tests:
rmin, rmax = -5.0, +5.0
c = 4.0
threshold = 1e-4
x = np.arange(rmin, rmax, 0.1)
y = np.arange(rmin, rmax, 0.1)
x, y = np.meshgrid(x, y)
f = lambda x, y: y**2 - 4 * x
res_op = op(x, y, c, f, threshold)
res_vec = vectorized(x, y, c, f, threshold)
assert np.allclose(res_op, res_vec)
Upvotes: 2