CODEWITHSUNDEEP
javascriptregexecmascript-6
user10518298
user10518298

Reputation: 189

JavaScript add space to a string after 2 characters but ignore newline character

I have to insert a space after every two characters in a string but by completely ignoring the newline character. I am able to do the spacing part but the problem comes with the newline as that is also counted as a character and when rendering the string it adds space at wrong positions.

let str = '23456\n734526754'
console.log(str)

str = str.match(/.{2}/g).join(' ');
console.log(str)

For the above code the output comes as

23 45 67 
3 45 26 75 3

What should be the ideal output is

23 45 67 
34 52 67 53

How can I ignore the newline character completely?

Upvotes: 2

Views: 675

Answers (3)

NIKUNJ KOTHIYA
NIKUNJ KOTHIYA

Reputation: 2165

You need to update your code.

let str = '234562\n7345267542';
str = str.replace(/(.{2})/g, "$1 ").trim();
console.log(str);

Solution details :

1. expression .{2} matches two characters
2. $1 is for adding space after each group of 2 character
3. g is for match all values
4. trim method removes any leading and trailing whitespace from string

Upvotes: 2

anubhava
anubhava

Reputation: 785641

You may use this spacer function in Javascript:

function spacer(s) {
   return s
     .replace(/^((?:.{2})*.)\n(.)(.*)/g, '$1$2\n$3')
     .replace(/.{2}(?=.)/g, '$& ');
}

console.log(spacer('23456\n734526754'));
//=> '23 45 67\n34 52 67 54'

console.log(spacer('234562\n7345267542'));
//=> '23 45 62\n73 45 26 75 42'

Solution Details:

  • spacer function user 2 .replace invocations
  • First .replace finds \n after matching odd number of characters and moves it one position ahead using 3 capture groups
  • Second .replace matches a pair of any characters (except line break) and inserts a space after the match

Upvotes: 1

Tim Biegeleisen
Tim Biegeleisen

Reputation: 522211

Here is an approach using a single regex replacement:

var str = '23456\n734526754';
var output = str.replace(/(\S{1,2})(?=\S)/g, "$1 ");
console.log(output);

The regex pattern used here says to match:

  • (\S{1,2}) match AND capture either 1 or 2 non whitespace characters
  • (?=\S) assert that non whitespace follows (do not add space after final group)

Then, we replace with $1 to effectively add a space after each group.

Upvotes: 0

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