Reputation: 113
I have a folder structure as below : Referring to the structure below, I am trying to access from the python file named 'MyFile.py', the csv file "sample4.csv" that is within the subdirectory "2021" (folder within 'yearlydata_subfolder2').
I've tried using os.path with the code below, but that doesn't seem to work and it returns 'FileNotFoundError'. Could someone please help?
C:.
├───1. Parent Folder :
│ 'Myfile.py'
├───2. 'data' (subfolder1)
├───3. 'AWSyearly' (subfolder2)
├───3.1. '2020' (folder within 'yearlydata_subfolder2')
sample1.csv (file in folder '2020')
├───3.1.1 monthlydata_2020 (subfolder within 2020)
sample2_2020_Jan.csv
sample3_2020_Feb.csv
├───3.2 '2021' (folder within 'yearlydata_subfolder2')
sample4.csv (file in folder '2021')
├───3.2.1 monthlydata_2021 (subfolder within 2021)
sample5_2021_Jan.csv
sample6_2021_Feb.csv
Code:
def access_csv():
path = os.path.realpath(os.path.join(os.getcwd(),os.path.dirname(__file__)))
print("Path of csv is:", path)
for root, dirs, files in os.walk(path):
for file in files:
if file.startswith('sample4') and file.endswith(".csv"):
df = pd.read_csv(file, decimal=",", delimiter=";", index_col=0)
return df
Upvotes: 0
Views: 62