Reputation: 4833
In jQuery if we use .remove()
for removing some element, then all bound events and jQuery data associated with the elements are removed.
But what happens if we "remove" the elements with .html()
?
Do we need to unbind all the elements prior to change any html for avoiding memory leaks?
Upvotes: 16
Views: 4582
Reputation: 923
yes, better to move elements you not need them to be lost to another display none container but use JavaScript appendChild
method as it not copy element it just send the element from one container to another so you not lose event listeners this way.
ex
<div id="hidden_container" style="display:none;"></div>
<script>
$("#hidden_container").get(0).appendChild("#elm_with_event").get(0));
</script>
Upvotes: 0
Reputation: 13589
Just to expand a bit:
.remove()
, .html()
, .empty()
, etc - all remove listeners.detach()
does not remove listeners.clone()
has parameters letting you decide if data/listeners are copied So if you want to retain listeners, use .detach()
.
Upvotes: 1
Reputation: 1021
Yes, they will be removed. jQuery will clean up events etc related to the removed elements. It will NOT copy events if you do something like $(elm1).html($elm2.html())
Upvotes: 17
Reputation: 141859
Yeah, they will be removed even when you use html()
. The jQuery source code confirms it.
Upvotes: 13