CODEWITHSUNDEEP
pythonstringlistformattingstring-formatting
SabreWolfy
SabreWolfy

Reputation: 5540

Using Python String Formatting with Lists

I construct a string s in Python 2.6.5 which will have a varying number of %s tokens, which match the number of entries in list x. I need to write out a formatted string. The following doesn't work, but indicates what I'm trying to do. In this example, there are three %s tokens and the list has three entries.

s = '%s BLAH %s FOO %s BAR'
x = ['1', '2', '3']
print s % (x)

I'd like the output string to be:

1 BLAH 2 FOO 3 BAR

Upvotes: 146

Views: 370155

Answers (8)

ryanjdillon
ryanjdillon

Reputation: 18948

For just filling in an arbitrary list of values to a string, you could do the following, which is the same as @neobot's answer but a little more modern and succinct.

>>> l = range(5)
>>> " & ".join(["{}"]*len(l)).format(*l)
'0 & 1 & 2 & 3 & 4'

If what you are concatenating together is already some kind of structured data, I think it would be better to do something more like:

>>> data = {"blah": 1, "foo": 2, "bar": 3}
>>> " ".join([f"{k} {v}" for k, v in data.items()])
'blah 1 foo 2 bar 3'

Upvotes: 7

Cédric Julien
Cédric Julien

Reputation: 80761

You should take a look to the format method of python. You could then define your formatting string like this :

>>> s = '{0} BLAH BLAH {1} BLAH {2} BLAH BLIH BLEH'
>>> x = ['1', '2', '3']
>>> print s.format(*x)
'1 BLAH BLAH 2 BLAH 3 BLAH BLIH BLEH'

Upvotes: 193

arun n a
arun n a

Reputation: 906

x = ['1', '2', '3']
s = f"{x[0]} BLAH {x[1]} FOO {x[2]} BAR"
print(s)

The output is

1 BLAH 2 FOO 3 BAR

Upvotes: 1

geekidharsh
geekidharsh

Reputation: 3589

Here is a one liner. A little improvised answer using format with print() to iterate a list.

How about this (python 3.x):

sample_list = ['cat', 'dog', 'bunny', 'pig']
print("Your list of animals are: {}, {}, {} and {}".format(*sample_list))

Read the docs here on using format().

Upvotes: 31

Joran Beasley
Joran Beasley

Reputation: 113930

Since I just learned about this cool thing(indexing into lists from within a format string) I'm adding to this old question. 

s = '{x[0]} BLAH {x[1]} FOO {x[2]} BAR'
x = ['1', '2', '3']
print (s.format (x=x))

Output:

1 BLAH 2 FOO 3 BAR

However, I still haven't figured out how to do slicing(inside of the format string '"{x[2:4]}".format...,) and would love to figure it out if anyone has an idea, however I suspect that you simply cannot do that.

Upvotes: 22

Matt P
Matt P

Reputation: 2347

This was a fun question! Another way to handle this for variable length lists is to build a function that takes full advantage of the .format method and list unpacking. In the following example I don't use any fancy formatting, but that can easily be changed to suit your needs.

list_1 = [1,2,3,4,5,6]
list_2 = [1,2,3,4,5,6,7,8]

# Create a function that can apply formatting to lists of any length:
def ListToFormattedString(alist):
    # Create a format spec for each item in the input `alist`.
    # E.g., each item will be right-adjusted, field width=3.
    format_list = ['{:>3}' for item in alist] 

    # Now join the format specs into a single string:
    # E.g., '{:>3}, {:>3}, {:>3}' if the input list has 3 items.
    s = ','.join(format_list)

    # Now unpack the input list `alist` into the format string. Done!
    return s.format(*alist)

# Example output:
>>>ListToFormattedString(list_1)
'  1,  2,  3,  4,  5,  6'
>>>ListToFormattedString(list_2)
'  1,  2,  3,  4,  5,  6,  7,  8'

Upvotes: 12

neobot
neobot

Reputation: 1220

Following this resource page, if the length of x is varying, we can use:

', '.join(['%.2f']*len(x))

to create a place holder for each element from the list x. Here is the example:

x = [1/3.0, 1/6.0, 0.678]
s = ("elements in the list are ["+', '.join(['%.2f']*len(x))+"]") % tuple(x)
print s
>>> elements in the list are [0.33, 0.17, 0.68]

Upvotes: 45

infrared
infrared

Reputation: 3626

print s % tuple(x)

instead of 

print s % (x)

Upvotes: 129

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