Reputation: 2863
Question:
How to display the value of a C++ iterator using WinDbg, illustrated below:
for (vector<string>::iterator i = args.begin(); i != args.end(); i++)
//omitted
//for instance:
} else if (*i == "-i") {//attempting to display the value of *i
++i;
if (!::PathFileExistsA(i->c_str()))
{
Note:
Using ?? evaluate C++ expression command, which displays the following:
0:000> ?? i
class std::_Vector_iterator<std::basic_string<char,
std::char_traits<char>,
std::allocator<char> >,
std::allocator<std::basic_string<char,
std::char_traits<char>,
std::allocator<char> > > >
+0x000 _Mycont : 0x0012ff40 std::_Container_base_secure
+0x004 _Mynextiter : (null)
+0x008 _Myptr : 0x009c6198
std::basic_string<char,std::char_traits<char>,std::allocator<char> >
*i
- please correct me if I'm wrongUpvotes: 7
Views: 11032
Reputation: 45493
The difficulty is that *i
invokes a function call to operator*
on the iterator. The string you want is likely being pointed to by _Myptr
at 0x009c6198
.
Upvotes: 1
Reputation: 54600
Try:
dt -r i
Which will recursively dump the iterator. One of the members should be the info you seek. Verbose, but effective.
Upvotes: 9