How to convert string to bytes in Python 3

Question

TypeError: 'str' does not support the buffer interface suggests two possible methods to convert a string to bytes:

b = bytes(mystring, 'utf-8')

b = mystring.encode('utf-8')

What are the differences between them? Which one should I opt for and why?

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_{See Convert bytes to a string in Python 3 for the other way around.}

Answer 1

How about the Python 3 'memoryview' way.

Memoryview is a sort of mishmash of the byte/bytearray and struct modules, with several benefits.

• Not limited to just text and bytes, handles 16 and 32 bit words too
• Copes with endianness
• Provides a very low overhead interface to linked C/C++ functions and data

Simplest example, for a byte array:

memoryview(b"some bytes").tolist()

[115, 111, 109, 101, 32, 98, 121, 116, 101, 115]

Or for a unicode string, (which is converted to a byte array)

memoryview(bytes("\u0075\u006e\u0069\u0063\u006f\u0064\u0065\u0020", "UTF-16")).tolist()

[255, 254, 117, 0, 110, 0, 105, 0, 99, 0, 111, 0, 100, 0, 101, 0, 32, 0]

#Another way to do the same
memoryview("\u0075\u006e\u0069\u0063\u006f\u0064\u0065\u0020".encode("UTF-16")).tolist()

[255, 254, 117, 0, 110, 0, 105, 0, 99, 0, 111, 0, 100, 0, 101, 0, 32, 0]

Perhaps you need words rather than bytes?

memoryview(bytes("\u0075\u006e\u0069\u0063\u006f\u0064\u0065\u0020", "UTF-16")).cast("H").tolist()

[65279, 117, 110, 105, 99, 111, 100, 101, 32]

memoryview(b"some  more  data").cast("L").tolist()

[1701670771, 1869422624, 538994034, 1635017060]

Word of caution. Be careful of multiple interpretations of byte order with data of more than one byte:

txt = "\u0075\u006e\u0069\u0063\u006f\u0064\u0065\u0020"
for order in ("", "BE", "LE"):
    mv = memoryview(bytes(txt, f"UTF-16{order}"))
    print(mv.cast("H").tolist())

[65279, 117, 110, 105, 99, 111, 100, 101, 32]
[29952, 28160, 26880, 25344, 28416, 25600, 25856, 8192]
[117, 110, 105, 99, 111, 100, 101, 32]

Not sure if that's intentional or a bug but it caught me out!!

The example used UTF-16, for a full list of codecs see Codec registry in Python 3.10

Answer 2

It's easier than it is thought:

my_str = "hello world"
my_str_as_bytes = str.encode(my_str)
print(type(my_str_as_bytes)) # ensure it is byte representation
my_decoded_str = my_str_as_bytes.decode()
print(type(my_decoded_str)) # ensure it is string representation

you can verify by printing the types. Refer to output below.

<class 'bytes'>
<class 'str'>

Answer 3

If you look at the docs for bytes, it points you to bytearray:

bytearray([source[, encoding[, errors]]])

Return a new array of bytes. The bytearray type is a mutable sequence of integers in the range 0 <= x < 256. It has most of the usual methods of mutable sequences, described in Mutable Sequence Types, as well as most methods that the bytes type has, see Bytes and Byte Array Methods.

The optional source parameter can be used to initialize the array in a few different ways:

If it is a string, you must also give the encoding (and optionally, errors) parameters; bytearray() then converts the string to bytes using str.encode().

If it is an integer, the array will have that size and will be initialized with null bytes.

If it is an object conforming to the buffer interface, a read-only buffer of the object will be used to initialize the bytes array.

If it is an iterable, it must be an iterable of integers in the range 0 <= x < 256, which are used as the initial contents of the array.

Without an argument, an array of size 0 is created.

So bytes can do much more than just encode a string. It's Pythonic that it would allow you to call the constructor with any type of source parameter that makes sense.

For encoding a string, I think that some_string.encode(encoding) is more Pythonic than using the constructor, because it is the most self documenting -- "take this string and encode it with this encoding" is clearer than bytes(some_string, encoding) -- there is no explicit verb when you use the constructor.

I checked the Python source. If you pass a unicode string to bytes using CPython, it calls PyUnicode_AsEncodedString, which is the implementation of encode; so you're just skipping a level of indirection if you call encode yourself.

Also, see Serdalis' comment -- unicode_string.encode(encoding) is also more Pythonic because its inverse is byte_string.decode(encoding) and symmetry is nice.

Answer 4

Answer for a slightly different problem:

You have a sequence of raw unicode that was saved into a str variable:

s_str: str = "\x00\x01\x00\xc0\x01\x00\x00\x00\x04"

You need to be able to get the byte literal of that unicode (for struct.unpack(), etc.)

s_bytes: bytes = b'\x00\x01\x00\xc0\x01\x00\x00\x00\x04'

Solution:

s_new: bytes = bytes(s, encoding="raw_unicode_escape")

Reference (scroll up for standard encodings):

Python Specific Encodings

Answer 5

The absolutely best way is neither of the 2, but the 3rd. The first parameter to encode defaults to 'utf-8' ever since Python 3.0. Thus the best way is

b = mystring.encode()

This will also be faster, because the default argument results not in the string "utf-8" in the C code, but NULL, which is much faster to check!

Here be some timings:

In [1]: %timeit -r 10 'abc'.encode('utf-8')
The slowest run took 38.07 times longer than the fastest. 
This could mean that an intermediate result is being cached.
10000000 loops, best of 10: 183 ns per loop

In [2]: %timeit -r 10 'abc'.encode()
The slowest run took 27.34 times longer than the fastest. 
This could mean that an intermediate result is being cached.
10000000 loops, best of 10: 137 ns per loop

Despite the warning the times were very stable after repeated runs - the deviation was just ~2 per cent.

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Using encode() without an argument is not Python 2 compatible, as in Python 2 the default character encoding is ASCII.

>>> 'äöä'.encode()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 0: ordinal not in range(128)