CODEWITHSUNDEEP
php
lisovaccaro
lisovaccaro

Reputation: 33946

Remove everything but the domain with PHP

My current js formula removes http://, https://, www and anything after '/'.

   function cleanUrl(url) { 
        return url.replace(/^(http(s)?:\/\/)?(www\.)?/gi,"");
    }

E.G: http://www.google.com/piza returns google.com

How can I do remove everything but the domain in one step but with PHP?

Upvotes: 3

Views: 1565

Answers (5)

Bankzilla
Bankzilla

Reputation: 2096

There is a much easier way ;)

<?php
   echo $_SERVER['HTTP_HOST']
?>

Upvotes: -4

hakre
hakre

Reputation: 197624

You can combine the regex you have (with a little modification) and Use parse_url()Docs to do the main work:

function cleanUrl($url) { 
    return preg_replace('/^(www\.)?/i',"", parse_url($url, PHP_URL_HOST));
}

As ceejayoz wrote, you might want to keep www. as part of the domain name.

Upvotes: 0

Vitor M
Vitor M

Reputation: 967

The function parse_url() is quite powerful, and the example usage from php.net will shed some light on what kinds of things you can do with it:

<?php
$url = 'http://username:password@hostname/path?arg=value#anchor';

print_r(parse_url($url));

echo parse_url($url, PHP_URL_PATH);
?>

The above example will output:

Array
(
    [scheme] => http
    [host] => hostname
    [user] => username
    [pass] => password
    [path] => /path
    [query] => arg=value
    [fragment] => anchor
)

Upvotes: 0

xthexder
xthexder

Reputation: 1565

You could use preg_replace with your current regex and get the same result: http://php.net/manual/en/function.preg-replace.php

Upvotes: 2

ceejayoz
ceejayoz

Reputation: 179994

Use parse_url().

$domain = parse_url($url, PHP_URL_HOST);

Do note that www.example.com and example.com are technically entirely separate entities that can point at totally different sets of records.

Upvotes: 8

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