CODEWITHSUNDEEP
javascriptjqueryformsselector
shub
shub

Reputation: 1052

Selected selector in JavaScript

How can I transform the following jQuery code to working JavaScript code?

jQuery

$('select :visible:selected').each(function(i) {
  // instructions
}

The visible selector I've already implemented with JS. Or is there a better solution?

JavaScript

for (var i=0;i<$('select').length;i++) {
  if ($('select')[i].style.visibility == "visible") {
    // instructions
  }    
}

Thanks for your help!

Upvotes: 1

Views: 333

Answers (2)

Jan Pfeifer
Jan Pfeifer

Reputation: 2861

Selected takes selected OPTION from SELECT list. So to get all selected options from all visible SELECTs from the page with pure JavaScript

var selects = document.getElementsByTagName('select');
for(var i=0; i<selects.length; i++) {
   var select = selects[i];

   if(select.style.visibility == 'visible'){
     for(var j=0; j<select.options.length; j++) {
       if(select.options[j].selected){
          // ... your code goes here ..
       }
     }
   }
}

UPDATE So if I undestand you corectly you need all selected OPTIONS from ALL visible SELECTs and you CAN use jQuery

$('select:visible option:selected').each(function(i,elm) {
  // instructions
  alert(elm.value);
 });

Upvotes: 4

oezi
oezi

Reputation: 51807

iQuery is javascript, so the "jQuery code" is working JavaScript code.

additionally, the fact that you're using in your second example, too ($('select')) makes me wonder why you don't just simply use your first one.

if you don't want to use jQuery and stick to "plain" javascript instead, it should look like this:

var elements = document.getElementsByTagName('select');
for (var i=0;i<elements.length;i++) {
  var element = elements[i];

  // use:
  element.style.visibility // to check for visibility
  element.selectedIndex // to check if/what option is selected (-1 = no selection)
  // a 'select' doesn't have a 'selected' property
  // because it's the <option> that gets selected

  // so we end up:
  if (element.style.visibility == "visible" && element.selectedIndex >= 0) {
    // instructions
  } 
}

more information about selectedindex and selected

Upvotes: 3

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