Reputation: 1
I am using Max(Index to find the data in a table with the search query being the date. i also need the data 1 cell to the right of the date column.
I have tried Offset(Max(Index but that just yielded a reference error. i have tried searching online but have found no other way of doing this. What i expected to happen was the data 1 cell to the right of the search query was found and pulled to the spreadsheet. below is the formula used that did not work
=OFFSET(MAX(INDEX((D16='Sheet1'!B$2:B$7500)*'Sheet1'!C$2:C$7500,)),0,1)
attached is some sample data from sheet 1
search query | date | cost |
---|---|---|
100336288 | 11 July 2023 | -£200.00 |
100025143 | 11 July 2023 | -£50.00 |
100301369 | 11 July 2023 | -£5,771.40 |
100280645 | 11 July 2023 | -£500.00 |
100138224 | 11 July 2023 | -£50.00 |
100336288 | 30 June 2023 | -£3,000.00 |
100336288 | 26 June 2023 | -£999.51 |
100280645 | 20 June 2023 | -£167.36 |
100280645 | 20 June 2023 | -£332.64 |
100025143 | 14 June 2023 | -£50.00 |
100138224 | 12 June 2023 | -£50.00 |
100336288 | 07 June 2023 | -£200.00 |
100336288 | 06 June 2023 | -£700.00 |
100336288 | 02 June 2023 | -£1,500.00 |
100301369 | 02 June 2023 | -£3,000.00 |
100138224 | 12 May 2023 | -£50.00 |
100336288 | 09 May 2023 | -£200.00 |
100025143 | 08 May 2023 | -£50.00 |
100336288 | 04 May 2023 | -£700.00 |
100336288 | 13 April 2023 | -£200.00 |
100025143 | 12 April 2023 | -£50.00 |
100336288 | 04 April 2023 | -£700.00 |
100336288 | 13 March 2023 | -£804.44 |
100025143 | 11 March 2023 | -£50.00 |
100336288 | 07 March 2023 | -£700.00 |
100336288 | 06 March 2023 | -£200.00 |
100025143 | 10 February 2023 | -£50.00 |
100336288 | 06 February 2023 | -£200.00 |
100336288 | 06 February 2023 | -£982.00 |
100336288 | 06 February 2023 | -£700.00 |
100025143 | 17 January 2023 | -£50.00 |
100336288 | 09 January 2023 | -£200.00 |
100025143 | 06 January 2023 | -£50.00 |
100336288 | 05 January 2023 | -£982.00 |
sheet 2 sample data i have removed the = to paste it here.
search query | Date |
---|---|
100025143 | MAX(INDEX((A2=Sheet1!A$1:A$7335)*Sheet1!B$1:B$7335,)) |
100138224 | MAX(INDEX((A3=Sheet1!A$1:A$7335)*Sheet1!B$1:B$7335,)) |
100280645 | MAX(INDEX((A4=Sheet1!A$1:A$7335)*Sheet1!B$1:B$7335,)) |
100301369 | MAX(INDEX((A5=Sheet1!A$1:A$7335)*Sheet1!B$1:B$7335,)) |
100336288 | MAX(INDEX((A6=Sheet1!A$1:A$7335)*Sheet1!B$1:B$7335,)) |
100283819 | MAX(INDEX((A7=Sheet1!A$1:A$7335)*Sheet1!B$1:B$7335,)) |
100281696 | MAX(INDEX((A8=Sheet1!A$1:A$7335)*Sheet1!B$1:B$7335,)) |
100149591 | MAX(INDEX((A9=Sheet1!A$1:A$7335)*Sheet1!B$1:B$7335,)) |
100099054 | MAX(INDEX((A10=Sheet1!A$1:A$7335)*Sheet1!B$1:B$7335,)) |
Upvotes: 0
Views: 66
Reputation: 114
VLOOKUP does exactly this - it looks for a value in the first column of a matrix, and when found one, it returns the value of a cell in a later column in the same line. The syntax goes:
VLOOKUP(lookup_value, table_array, col_index_num, [range_lookup])
where
Keep in mind that
p.s.: In the newer excel versions you also have XLOOKUP as an improvement/ enhancement over VLOOKUP.
Upvotes: 0