Reputation: 20906
ex.Message = "ORA-20586: SOME TEXT SOME TEXT.\nORA-06512: at \"RMM.LOKAC\", line 116\nORA-06512: at line 2"
catch (Exception ex)
MessageBox.Show(ex.Message);
return false;
}
ex.Message = "ORA-20586: SOME TEXT SOME TEXT.\nORA-06512: at \"RMM.LOKAC\", line 116\nORA-06512: at line 2"
but i need to get just "SOME TEXT SOME TEXT". How can i read just text.
ORA-20586 means user error http://www.dbmotive.com/support/oracle-error-codes/?type=ORA&errcode=20586
Database is Oracle. How can i read just "SOME TEXT SOME TEXT" from this error message.
Upvotes: 0
Views: 1255
Reputation:
It is always better to catch the exception, then write a more user friendly message. You never want to expose the underlying architecture of your application, if possible.
bool success = false;
try {
// you code
success = true; // Notice: Last call of your try routine.
} catch (Exception ex {
if (-1 < ex.Message.IndexOf("ORA-20586")) {
MessageBox.Show("user error");
} else {
MessageBox.Show(ex.Message);
}
}
return success;
Upvotes: 0
Reputation: 94645
There are number of ways to extract the string. You may try String split, regular expression split or string index search.
Upvotes: 2