CODEWITHSUNDEEP
xslt-1.0apply-templates
Andrew Truckle
Andrew Truckle

Reputation: 19197

Using xsl:apply-templates with conditional filtering

This snippet works correctly:

<xsl:template match="msa:Group">
    <h2>
        <xsl:value-of select="."/>
    </h2>

    <xsl:variable name="iGroupId" select="@Id"/>

    <xsl:apply-templates select="$PubDB/msa:PublisherDatabase/msa:Publishers/msa:Publisher[msa:GroupId=$iGroupId]">
            <xsl:sort select="msa:Name" data-type="text" order="ascending"/>
    </xsl:apply-templates>
</xsl:template>

What I want to know is why I had to save @Id to a variable and use that in the xpath statement. This failed:

select="$PubDB/msa:PublisherDatabase/msa:Publishers/msa:Publisher[msa:GroupId=@Id]"

Upvotes: 1

Views: 30

Answers (1)

michael.hor257k
michael.hor257k

Reputation: 117100

Your attempt:

select="$PubDB/msa:PublisherDatabase/msa:Publishers/msa:Publisher[msa:GroupId=@Id]"

would select all msa:Publisher elements whose msa:GroupId child is equal to their @Id attribute.

In order to refer to the @Id attribute of the current msa:Group element, you need to use the current() function:

select="$PubDB/msa:PublisherDatabase/msa:Publishers/msa:Publisher[msa:GroupId=current()/@Id]"

Read the explanation in the specification:
https://www.w3.org/TR/1999/REC-xslt-19991116/#function-current

P.S Consider using a key to resolve cross-references.

Upvotes: 2

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