CODEWITHSUNDEEP
javadatetimedatetime
kolrie
kolrie

Reputation: 12742

Compare only the time portion of two dates, ignoring the date part

What's a good method to, given two Date objects, compare the difference between their time portion only, completely ignoring Year, Month and Day?

It's quite the opposite of this question.

UPDATE: Here's the final code for future reference:

private long differenceBetween(Date currentTime, Date timeToRun)
{
    Calendar currentCal = Calendar.getInstance();
    currentCal.setTime(currentTime);

    Calendar runCal = Calendar.getInstance();
    runCal.setTime(timeToRun);
    runCal.set(Calendar.DAY_OF_MONTH, currentCal.get(Calendar.DAY_OF_MONTH));
    runCal.set(Calendar.MONTH, currentCal.get(Calendar.MONTH));
    runCal.set(Calendar.YEAR, currentCal.get(Calendar.YEAR));

    return currentCal.getTimeInMillis() - runCal.getTimeInMillis();
}

Upvotes: 36

Views: 41963

Answers (8)

Basil Bourque
Basil Bourque

Reputation: 340280

tl;dr

Duration                                  // Span of time, with resolution of nanoseconds.
.between(                                 // Calculate elapsed time.
    LocalTime.now(                        // Get current time-of-day…
        ZoneId.of( "Pacific/Auckland" )   // … as seen in a particular time zone.
    )                                     // Returns a `LocalTime` object.
    ,
    myJavaUtilDate                        // Avoid terrible legacy date-time classes such as `java.util.Date`.
    .toInstant()                          // Convert from `java.util.Date` to `java.time.Instant`, both representing a moment in UTC.
    .atZone(                              // Adjust from UTC to a particular time zone. Same moment, same point on the timeline, different wall-clock time.
        ZoneId.of( "Pacific/Auckland" )   // Specify time zone by proper naming in `Continent/Region` format, never 2-4 letter pseudo-zones such as `PST`, `CEST`, `CST`, `IST`, etc.
    )                                     // Returns a `ZonedDateTime` object.
    .toLocalTime()                        // Extract the time-of-day without the date and without a time zone.
)                                         // Returns a `Duration` object.
.toMillis()                               // Calculate entire span-of-time in milliseconds. Beware of data-loss as `Instant` uses a finer resolution the milliseconds, and may carry microseconds or nanoseconds.

I suggest passing around the type-safe and self-explanatory Duration object rather than a mere integer number of milliseconds.

java.time

The modern approach uses the java.time classes that supplanted the terrible legacy classes such as Date, Calendar, SimpleDateFormat.

Table of all date-time types in Java, both modern and legacy

Convert your java.util.Date (a moment in UTC), to an Instant. Use new conversion methods added to the old classes.

Instant instant = myJavaUtilDate.toInstant() ;

That represents a moment in UTC. Determining a date and a time-of-day requires a time zone . For any given moment, the date and time vary around the globe by zone. For example, a few minutes after midnight in Paris France is a new day while still “yesterday” in Montréal Québec.

If no time zone is specified, the JVM implicitly applies its current default time zone. That default may change at any moment during runtime(!), so your results may vary. Better to specify your desired/expected time zone explicitly as an argument.

Specify a proper time zone name in the format of continent/region, such as America/Montreal, Africa/Casablanca, or Pacific/Auckland. Never use the 2-4 letter abbreviation such as EST or IST as they are not true time zones, not standardized, and not even unique(!). 

ZoneId z = ZoneId.of( "America/Montreal" ) ;

If you want to use the JVM’s current default time zone, ask for it and pass as an argument. If omitted, the JVM’s current default is applied implicitly. Better to be explicit, as the default may be changed at any moment during runtime by any code in any thread of any app within the JVM.

ZoneId z = ZoneId.systemDefault() ;  // Get JVM’s current default time zone.

Assign the ZoneId to the Instant to produce a ZonedDateTime object.

ZonedDateTime zdt = instant.atZone( z ) ;

Extract the time-of-day portion, without the date and without the time zone.

LocalTime lt = zdt.toLocalTime() ;

Compare. Calculate elapsed time with a Duration. 

Duration d = Duration.between( ltStart , ltStop ) ;

Be aware that this is not a fair comparison. Days are not always 24-hours long, and not all time-of-day values are valid on all days in all zones. For example, in the United States during a Daylight Saving Time cutover, there may not be a 2 AM hour at all. So 1 AM to 4 AM may be 3 hours on one date but only 2 hours on another date.

About java.time

The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.

The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.

To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.

You may exchange java.time objects directly with your database. Use a JDBC driver compliant with JDBC 4.2 or later. No need for strings, no need for java.sql.* classes.

Where to obtain the java.time classes?

Table of which java.time library to use with which version of Java or Android

The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time. You may find some useful classes here such as Interval, YearWeek, YearQuarter, and more.

Upvotes: 7

Amit
Amit

Reputation: 1672

if you just want to compare the time part of the dates then this would give you the right result - 

public long compareTimes(Date d1, Date d2)
    {
        long     t1;
        long     t2;
        t1 = d1.getHours()*60*60+d1.getMinutes()*60+d1.getSeconds();
        t2 = d2.getHours()*60*60+d2.getMinutes()*60+d2.getSeconds();
        long diff = t1-t2;
        System.out.println("t1 - "+t1+", t2 - "+t2+",  diff - "+diff);

        return diff;
    }

Upvotes: 1

David R Tribble
David R Tribble

Reputation: 12214

If you want to compare the underlying binary (long int) values of the dates, you can do this:

public int compareTimes(Date d1, Date d2)
{
    int     t1;
    int     t2;

    t1 = (int) (d1.getTime() % (24*60*60*1000L));
    t2 = (int) (d2.getTime() % (24*60*60*1000L));
    return (t1 - t2);
}

Addendum 1

This technique has the advantage of speed, because it uses the underlying long value of the Date objects directly, instead of converting between ticks and calendar components (which is rather expensive and slow). It's also a lot simpler than messing with Calendar objects.

Addendum 2

The code above returns the time difference as an int, which will be correct for any pair of times, since it ignores the year/month/day portions of the dates entirely, and the difference between any two times is no more than 86,400,000 ms (= 1000 ms/sec × 60 sec/min × 60 min/hr × 24 hr/day).

Upvotes: 32

nicholas.hauschild
nicholas.hauschild

Reputation: 42834

Take a look at the Calendar class. It has support for extracting hours, minutes, and seconds from given Date's.

Calendar calendar = Calendar.getInstance();
calendar.setTime(yourDateObject);
int hour = calendar.get(Calendar.HOUR);
int minute = calendar.get(Calendar.MINUTE);
int second = calendar.get(Calendar.SECOND);

Upvotes: 5

Dennis Puzak
Dennis Puzak

Reputation: 3736

Dont know how good practiced or efficent is this one but i've written a simple function using the Date object that serves my purposes. It returns a true or false is the first date value bigger than the second. The inputs d1 && d2 are Date objects.

function CompareTimes(d1, d2) {
             if (d1.getHours() < d2.getHours()) {
                 return false;
             }
             if (d1.getHours() > d2.getHours()) {
                 return true;

             } else {
                 return (d1.getMinutes() > d2.getMinutes());
             }
};

Upvotes: 2

vanto
vanto

Reputation: 3142

If JODA is not an option, one of the shortest approaches is probably to convert the time to strings and then compare them.

DateFormat df = new SimpleDateFormat("HHmmssSZ");
df.format(date1).equals(df.format(date2));

Upvotes: 1

James
James

Reputation: 432

You may consider using Joda time's DateTimeComparator.getTimeOnlyInstance() for a comparator that will compare two Joda dates based only upon the times.

For example:

DateTimeComparator comparator = DateTimeComparator.getTimeOnlyInstance();
comparator.compare(date1, date2);

See http://joda-time.sourceforge.net/api-release/org/joda/time/DateTimeComparator.html#getTimeOnlyInstance()

Upvotes: 21

bbaja42
bbaja42

Reputation: 2169

In case you can't use JODA,

create 2 calendar objects, set year, month and day to 0.

Compare them....

Upvotes: 4

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