CODEWITHSUNDEEP
pythonwindowspopen
v_y
v_y

Reputation: 325

python os.popen fails when given umlauted character

Under winxp (pro x64 version 2003, sp2), running the following at cmd prompt works fine:

dir C:\testüüüdirectory\

Please note the 'ü' character.

But from python 2.7.1.4, the following always returns an error code 1:

>>> res = os.popen("dir C:\\testüüüdirectory\\")
>>> res.close()
1
>>>

How can i get popen to accept the ü character?

Upvotes: 3

Views: 1579

Answers (2)

eswald
eswald

Reputation: 8406

This would probably be an encoding issue, where your input doesn't quite match what the file system expects on output. First, you'll need to tell Python what encoding your input uses, then what encoding the popen() call expects.

>>> filename = "C:\\testüüüdirectory\\".decode("utf-8")
>>> res = os.popen("dir " + filename.encode("cp1252"))

You may have to experiment with various encoding combinations to get the right pair. UTF-8, UTF-16, and cp1252 are the most likely candidates for Windows, but your system might be set up to use another encoding. If you're really lucky, os.popen() might even accept a Unicode string, in which case the encode() step could be skipped.

If you're really unlucky, character canonicalization could be an issue. There are two possible representations of "ü" in Unicode: U+00FC or U+0075 U+0308; the second is a "u" with a combining diaresis, while the first is pre-combined. If Windows expects one while encode() produces the other, you may have to work a bit to get the right string.

Upvotes: 3

chown
chown

Reputation: 52738

Try it with a u in front of the string:

 res = os.popen(u"dir C:\\testüüüdirectory\\")

More on unicode strings / lexical analysis

Check sys.getfilesystemencoding also to make sure you can have such file names.

Upvotes: 0

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