CODEWITHSUNDEEP
xmlxslt
EnexoOnoma
EnexoOnoma

Reputation: 8836

Simple IF statement in XSLT two remove one element if found

I transform some different structures of XML files at once using XSLT.

Some of them have a <link></link> element tag in their structure, and the others have either one of <feedburner:origLink></feedburner:origLink> and <link></link>, or both.

My question is how do I delete the <feedburner:origLink></feedburner:origLink> when is found with the <link></link> tag ?

This is what I use for now and some of the XMLs have two times a <url></url> element tag.

<xsl:template match="feedburner:origLink | link">
  <url>
        <xsl:apply-templates select="node() | @*" />
  </url>
</xsl:template>

Upvotes: 2

Views: 161

Answers (2)

Michael Kay
Michael Kay

Reputation: 163262

In XSLT 2.0 you might be able to use a solution along the lines of

<xsl:apply-templates select="(link, feedburner:origLink)[1]"/>

Upvotes: 1

evil otto
evil otto

Reputation: 10582

One approach is to match the element with a predicate specifying that the other one isn't there:

<xsl:template match="feedburner:origLink[not(../link)] | link">
  <url>
        <xsl:apply-templates select="node() | @*" />
  </url>
</xsl:template>

Upvotes: 0

Related Questions