CODEWITHSUNDEEP
c++
sukantk
sukantk

Reputation: 45

what is meant by this ....time1 >? = time2 in C++

just came through a statement in this is the code,,

what exactly does this line mean..? timeO >?= timeB;

using namespace std;

int main() {

    int tt = 0;

    int T; scanf("%d",&T); while (T--) {tt++;

        int N; scanf("%d",&N);

        int posO = 1, timeO = 0;

        int posB = 1, timeB = 0;

        char type[2]; int M;

        for (int i=0; i<N; i++) {

            scanf("%s %d",type,&M);

            if (type[0]=='O') {

                timeO += abs(M-posO);

                timeO >?= timeB;

                timeO++;

                posO = M;

            } else {

                timeB += abs(M-posB);

                timeB >?= timeO;

                timeB++;

                posB = M;                

            }

        }

        printf("Case #%d: %d\n",tt,max(timeO,timeB));

    }

}

Upvotes: 0

Views: 215

Answers (2)

sam
sam

Reputation: 1401

the point is you should convert it to second then the answer is clear 

int time1  = ((h1*60)*60)+(m1*60)+s1;
int time2  = ((h2*60)*60)+(m2*60)+s2;
    int result = time2-time1;

Upvotes: 0

Mat
Mat

Reputation: 206775

It's an old GCC extension Minimum and Maximum Operators in C++.

(Doesn't build with GCC 4.5 or above.)

Don't use it, it's not portable at all.

Upvotes: 2

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