Reputation: 109
I need to convert a string of numbers into a string of letters to form words Example: if the input to your program is 1920012532082114071825463219200125320615151209190846 it should return stay hungry. stay foolish.
I have this so far:
def number ():
output = []
input = raw_input ("please enter a string of numbers: ")
for number in input:
if number <= 26:
character = chr(int(number+96))
output.append(character)
else:
character = chr(int(number))
output.append(character)
print output
I need it to somehow determine that every two numbers equals one letter. I have a program that does the reverse of this, outputs numbers when given letter. this is what that looks like:
def word ():
output = []
input = raw_input("please enter a string of lowercase characters: ")
for character in input:
number = ord(character) - 96
if number > 0:
if number <= 9:
output.append('0' + str(number))
else:
output.append(str(number))
else:
output.append(str(number + 96))
print ''.join(output)
Thanks for the help
Upvotes: 1
Views: 6052
Reputation: 1
def remove(string):
return string.replace(" ", "")
dict =
{'a': '1',
'b': '2',
'c': '3',
'd': '4',
'e': '5',
'f': '6',
'g': '7',
'h': '8',
'i': '9',
'j': '10',
'k': '11',
'l': '12',
'm': '13',
'n': '14',
'o': '15',
'p': '16',
'q': '17',
'r': '18',
's': '19',
't': '20',
'u': '21',
'v': '22',
'w': '23',
'x': '24',
'y': '25',
'z': '26',
'1': 'a',
'2': 'b',
'3': 'c',
'4': 'd',
'5': 'e',
'6': 'f',
'7': 'g',
'8': 'h',
'9': 'i',
'10': 'j',
'11': 'k',
'12': 'l',
'13': 'm',
'14': 'n',
'15': 'o',
'16': 'p',
'17': 'q',
'18': 'r',
'19': 's',
'20': 't',
'21': 'u',
'22': 'v',
'23': 'w',
'24': 'x',
'25': 'y',
'26': 'z',
}
word =
remove(input(''))
for x in word:
print(dict[x])
Upvotes: 0
Reputation: 3107
''.join(map(lambda n: [chr(n),chr(n+96)][n<=26], map(int,map(''.join,zip(*[iter(s)]*2)))))
Upvotes: 0
Reputation: 63802
Make a single iterator to your input string, and call zip with it like:
it = iter(data)
pairs = zip(it, it)
Gives:
[('1', '9'), ('2', '0'), ('0', '1'), ('2', '5'), ('3', '2'), ('0', '8'), ('2', '1'), ('1', '4'), ('0', '7'), ('1', '8'), ('2', '5'), ('4', '6'), ('3', '2'), ('1', '9'), ('2', '0'), ('0', '1'), ('2', '5'), ('3', '2'), ('0', '6'), ('1', '5'), ('1', '5'), ('1', '2'), ('0', '9'), ('1', '9'), ('0', '8'), ('4', '6')]
Next pass this to map with a ''.join as the function to make integer strings:
>>> map(''.join, zip(it,it))
['19', '20', '01', '25', '32', '08', '21', '14', '07', '18', '25', '46', '32', '19', '20', '01', '25', '32', '06', '15', '15', '12', '09', '19', '08', '46']
Now pass this to map again, to convert to ints:
>>> map(int, map(''.join, zip(it,it)))
[19, 20, 1, 25, 32, 8, 21, 14, 7, 18, 25, 46, 32, 19, 20, 1, 25, 32, 6, 15, 15, 12, 9, 19, 8, 46]
Now pass this to map with a lambda to perform your decoding logic:
>>> map(lambda n : chr(n+96) if n < 27 else chr(n), map(int, map(''.join, zip(it,it))))
['s', 't', 'a', 'y', ' ', 'h', 'u', 'n', 'g', 'r', 'y', '.', ' ', 's', 't', 'a', 'y', ' ', 'f', 'o', 'o', 'l', 'i', 's', 'h', '.']
And lastly, pass this to ''.join:
>>> ''.join(map(lambda n : chr(n+96) if n < 27 else chr(n), map(int, map(''.join, zip(it,it)))))
'stay hungry. stay foolish.'
What could be simpler? :)
Upvotes: 4
Reputation: 34384
You can split up the str
into two-character chunks using zip()
and slicing with a step like this:
for pair in zip(input[::2], input[1::2]):
number = "".join(pair)
I'd write the whole thing like this:
def int_str_to_chr_str(int_str):
res = []
for pair in zip(int_str[::2], int_str[1::2]):
number = int("".join(pair))
if number <= 26:
number += 96
res.append(chr(number))
return "".join(res)
print int_str_to_chr_str("1920012532082114071825463219200125320615151209190846")
It's more useful to have the logic separated from input and output, so you can use the function in other parts of a program. It's also a good idea to avoid repeating the use of names like number
or input
(which is a built-in).
Upvotes: 1