Reputation: 149
If a function is declared non-virtual in a derived class when the base class function was virutal, why does it invoke a vtable lookup on calling the function on its pointer? The function is clear from the scope.
Upvotes: 13
Views: 3040
Reputation: 114599
In C++ if you declare a method virtual
in the base class then it's virtual also in derived class, even if the virtual
keyword is omitted.
For documentation purposes is however in my opinion nice to repeat it anyway.
Upvotes: 21
Reputation: 56549
Virtual methods created to affect on derived class (When you mark a method as virtual. It will use vtable on derived classes). And the overrided methods will be virtual.
Upvotes: 1
Reputation: 21214
You cannot make a function non-virtual, so it will stay virtual and a call to the function is in general also virtual. Of course, there are situations where the compiler will be able to optimize this and do a direct call, but apparantly not in your scenario.
Upvotes: 5
Reputation: 16046
The function is still virtual (assuming it has the same or a covariant signature). Using virtual
when overriding is redundant.
Upvotes: 2
Reputation: 12849
When a class inherits a virtual function, any new, overriding declaration of that function will automatically be made virtual, even if the virtual
keyword is not used.
Upvotes: 0