CODEWITHSUNDEEP
javascriptjqueryregex
Someone
Someone

Reputation: 10575

How do I write javascript Regex in such way it accepts 6 Characters

Javascript regex to validate that it contains 6 characters and in which one character (1) should be a number.

var pwdregex  =/^[A-Za-z1-9]{6}$/;

Upvotes: 3

Views: 235

Answers (3)

maerics
maerics

Reputation: 156464

[Edit] Fixed obvious bug...

If you are ok with using a function instead of a regex you can do this:

var sixAlphaOneDigit = function(s) {
  return !!((s.length==6) && s.replace(/\d/,'').match(/^[A-Za-z]{5}$/));
};

sixAlphaOneDigit('1ABCDE'); // => true
sixAlphaOneDigit('ABC1DE'); // => true
sixAlphaOneDigit('ABCDE1'); // => true
sixAlphaOneDigit('ABCDE'); // => false
sixAlphaOneDigit('ABCDEF'); // => false
sixAlphaOneDigit('ABCDEFG'); // => false

If you want to do it strictly in a regex then you could build a terribly long pattern which enumerates all possibilities of the position of the digit and the surrounding (or leading, or following) characters.

Upvotes: 3

ridgerunner
ridgerunner

Reputation: 34395

This will guarantee exactly one number (i.e. a non-zero decimal digit):

var pwdregex = /^(?=.{6}$)[A-Za-z]*[1-9][A-Za-z]*$/;

And this will guarantee one or more consecutive number:

var pwdregex = /^(?=.{6}$)[A-Za-z]*[1-9]+[A-Za-z]*$/;

And this will guarantee one or more not-necessarily-consecutive number:

var pwdregex = /^(?=.{6}$)[A-Za-z]*(?:[1-9][A-Za-z]*)+$/;

All of the above expressions require exactly six characters total. If the requirement is six or more characters, change the {6} to {6,} (or remove the $ from {6}$).

Upvotes: 11

FailedDev
FailedDev

Reputation: 26930

All possible combinations of 1 digit and alphanumeric chars with a length of 6.

if (subject.match(/^[a-z]{0,5}\d[a-z]{0,5}$/i) && subject.length == 6) {
    // Successful match
} else {
    // Match attempt failed
}

Upvotes: 4

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