CODEWITHSUNDEEP
javaspringspring-mvc
pihu
pihu

Reputation: 93

Spring model object

I want to set to different data,like 

    SoyMapData dataFormsMenu=new SoyMapData(
            "class","menu horizontal",
            "caption","",
            "id","dfMenu",
            "innerContainer","div",
            "helper","span",
            "items",new SoyListData( 
            new SoyMapData ("caption", "Manage Dataforms",
                    "class", "",
                    "link", "#"),
                    new SoyMapData("caption", "viewForm",
                    "class", "",
                    "link", "#")
                    ));
      SoyMapData mainMenu = new SoyMapData(
                "class","menu horizontal dropdown",
                "caption","",
                "id","mainMenu",
                "container","div",
                "contClass","navigation main left",
                "items",captionData);

into model object of spring,

model.addattribute("",mainmenu);
model.addattribute("",dfmenu);

how to do this in spring.

Upvotes: 1

Views: 2291

Answers (2)

Sean Patrick Floyd
Sean Patrick Floyd

Reputation: 298898

a) you are not talking about Spring, you are talking about Spring MVC, the MVC framework built upon the Spring framework. There's a difference.

b) you need to give the model attribute a name, e.g.

model.addattribute("main",mainmenu);
model.addattribute("df",dfmenu);

Then you can access the data from a JSP (or other view) using

${main.id} or ${main[id]},

depending on the inner workings of SoyMapData

Upvotes: 3

Bala
Bala

Reputation: 4547

create a bean for all simple objects; then connect them to get your complex object. For example, create a bean for each simple SoyMapData objects (one for "Manage Dataform, one for ""viewForm" ...), then use them to get dataFormsMenu bean object by setting property/via constructor

Upvotes: 0

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