Reputation: 1831
I'm trying an obvious task:
var maxVal = [ 1, 2, 3, 4, 5 ].reduce( Math.max, 0 );
and get:
NaN
as the result. To make it work I have to make an anonymous function this way:
var maxVal = [ 1, 2, 3, 4, 5 ].reduce( function ( a, b ) {
return Math.max(a, b);
}, 0 );
Could someone tell me why? Both are functions that take two arguments and both return one value. What's the difference?
Another example could be this:
var newList = [[1, 2, 3], [4, 5, 6]].reduce( Array.concat, [] );
The result is:
[1, 2, 3, 0, #1=[1, 2, 3], #2=[4, 5, 6], 4, 5, 6, 1, #1#, #2#]
I can run this example in node.js only under this shape (Array has no concat in node.js v4.12, which I use now):
var newList = [[1, 2, 3], [4, 5, 6]].reduce( [].concat, [] );
and then get this:
[ {}, {}, 1, 2, 3, 0, [ 1, 2, 3 ], [ 4, 5, 6 ], 4, 5, 6, 1, [ 1, 2, 3 ], [ 4, 5, 6 ] ]
And why is that?
Upvotes: 13
Views: 4869
Reputation: 45172
Since Math.max
accepts multiple arguments, you can just convert the array to a parameter list via the apply
function.
var maxVal = Math.max.apply(Math, [ 1, 2, 3, 4, 5 ]);
See warnings here on limitations of this technique.
Upvotes: 4
Reputation: 104800
Another way to reduce an array to its max value:
var maxVal = [ 1, 2, 3, 4, 5 ].reduce(function(a,b){return a>b?a:b});
(illustrating how reduce works, not that it is the best way to get the max number from an array)
Upvotes: 3
Reputation: 154898
The function passed to reduce
takes more than 2 arguments:
previousValue
currentValue
index
array
Math.max
will evaluate all arguments and return the highest:
Math.max(1, 2, 3, 4) === 4;
So in case of passing Math.max
to reduce
, it will return the highest value from the 4 arguments passed, of which one is an array. Passing an array will make Math.max
return NaN
because an array is not a number. This is in the specs (15.8.2.11):
Given zero or more arguments, calls ToNumber on each of the arguments and returns the largest of the resulting values.
...
If any value is NaN, the result is NaN
ToNumber
will return NaN
for an array.
So reducing with Math.max
will return NaN
in the end.
Upvotes: 24