Reputation: 1
/len = length, hei = height
/get and store input
input
store LEN
input
store HEI
/start of loop
/load in the value of len
LOOP, load LEN
/add len to num
add NUM
/store the value in num
Store NUM
/load in hei deduct 1 and store back to hei
load HEI
subt ONE
store HEI
/skip jump if the value in the ac is 0
skipcond 400
jump LOOP
/output
LOOP1, load NUM
subt TWO
store NUM
load NUM
output
skipcond 400
jump LOOP1
load NUM
/end the program
halt
LEN, DEC 0
HEI, DEC 0
ONE, DEC 1
NUM, DEC 0
TWO, DEC 2
I am attempting to make a program that calculates the area of a triangle. I've managed to get the multiplication part out of the way, however the division part is where I'm struggling. Any help would be appreciated.
I have attempted to make a second loop in which the final product would continually be subtracted by 2, however the output would just subtract 2 multiple times without getting the correct answer. For example: `
/len = 3, heigh = 4
/output would be:
/10
/8
/6
/4
/2
/0
Like I said before, any help would be appreciated.
Upvotes: 0
Views: 136
Reputation: 54767
Change your loop to track and return the quotient
LOOP1, load NUM
subt TWO
store NUM
load QUO <--
add ONE <--
store QUO <--
load NUM
output
skipcond 400
jump LOOP1
load QUO <--
/end the program
halt
and add:
QUO, DEC 0
Upvotes: 1