CODEWITHSUNDEEP
sqlmysqlwindow-functionsdense-rank
Shayma
Shayma

Reputation: 41

Dense_Rank keeps returning each row as 1?

I am playing around with a Netflix dataset from Kaggle on MySQL. The dataset contains fields such as Country, Subscription_Type, Age, Gender, Monthly_Revenue, etc. In the Subscription_Type column, the possible return fields are Basic, Standard, Premium. I am trying to find the most common subscription type for each country, so I'd ideally have one result per country.

SELECT * 
FROM (
    SELECT Country,
            Subscription_Type, 
            COUNT(*) as count_subscription, 
            DENSE_RANK() OVER (PARTITION BY Country ORDER BY (SELECT COUNT(*) as count_subscription FROM netflix) ) as `rnk`
    FROM netflix
    GROUP BY Country, Subscription_Type
) as subscription_rank
WHERE rnk = 1;

The problem I'm having is that Dense_Rank is ranking each row as 1, so I end up getting three results per country. How can I fix it so that I'm able to get the most popular subscription type per country?

Upvotes: 2

Views: 163

Answers (1)

Charlieface
Charlieface

Reputation: 72194

The subquery is nonsense: it's not correlated so returns the same result on every row.

Moreover, it's not necessary. Window functions work after aggregation, so you can just use COUNT(*) directly.

SELECT * 
FROM (
    SELECT nf.Country,
           nf.Subscription_Type, 
           COUNT(*) as count_subscription, 
           DENSE_RANK() OVER (PARTITION BY nf.Country ORDER BY COUNT(*)) as rnk
    FROM netflix nf
    GROUP BY
      nf.Country,
      nf.Subscription_Type
) as subscription_rank
WHERE rnk = 1;

I might be wrong, but maybe you wanted COUNT(*) DESC? Also DENSE_RANK will return tied results, whereas ROW_NUMBER does not.

Upvotes: 0

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