Reputation: 1333
I got String from the database which have multiple commas (,
) . I want to remove the last comma but I can't really find a simple way of doing it.
What I have: kushalhs, mayurvm, narendrabz,
What I want: kushalhs, mayurvm, narendrabz
Upvotes: 68
Views: 156745
Reputation: 1
package com.app;
public class SiftNumberAndEvenNumber {
public static void main(String[] args) {
int arr[] = {1,2,3,4,5};
int arr1[] = new int[arr.length];
int shiftAmount=3;
for(int i = 0; i < arr.length; i++){
int newLocation = (i + (arr.length - shiftAmount)) % arr.length;
arr1[newLocation] = arr[i];
}
for(int i=0;i<arr1.length;i++) {
if(i==arr1.length-1) {
System.out.print(arr1[i]);
}else {
System.out.print(arr1[i]+",");
}
}
System.out.println();
for(int i=0;i<arr1.length;i++) {
if(arr1[i]%2==0) {
System.out.print(arr1[i]+" ");
}
}
}
}
Upvotes: -2
Reputation: 16999
And one more ... this also cleans internal commas mixed with whitespace:
From , , , ,one,,, , ,two three, , , ,,four, , , , ,
to one,two three, four
text.replaceAll("^(,|\\s)*|(,|\\s)*$", "").replaceAll("(\\,\\s*)+", ",");
Upvotes: 3
Reputation: 1361
i am sharing code form my project using regular expression you can do this...
String ChildBelowList = "";
if (!Childbelow.isEmpty()) {
for (int iCB = 0; iCB < Childbelow.size(); iCB++) {
ChildBelowList = ChildBelowList += Childbelow.get(iCB) + ",";
}
ChildBelowList = ChildBelowList.replaceAll("(^(\\s*?\\,+)+\\s?)|(^\\s+)|(\\s+$)|((\\s*?\\,+)+\\s?$)", "");
tv_childbelow.setText(ChildBelowList);
} else {
ll_childbelow.setVisibility(View.GONE);
}
Upvotes: 0
Reputation: 4769
You can do something like using join function of String class.
import java.util.Arrays;
import java.util.List;
public class Demo {
public static void main(String[] args) {
List<String> items = Arrays.asList("Java", "Ruby", "Python", "C++");
String output = String.join(",", items);
System.out.println(output);
}
}
Upvotes: 2
Reputation: 1
Or something like this:
private static String myRemComa(String input) {
String[] exploded = input.split(",");
input="";
boolean start = true;
for(String str : exploded) {
str=str.trim();
if (str.length()>0) {
if (start) {
input = str;
start = false;
} else {
input = input + "," + str;
}
}
}
return input;
}
Upvotes: -1
Reputation: 197
public static String removeExtraCommas(String entry) {
if(entry==null)
return null;
String ret="";
entry=entry.replaceAll("\\s","");
String arr[]=entry.split(",");
boolean start=true;
for(String str:arr) {
if(!"".equalsIgnoreCase(str)) {
if(start) {
ret=str;
start=false;
}
else {
ret=ret+","+str;
}
}
}
return ret;
}
Upvotes: 0
Reputation: 99
(^(\s*?\,+)+\s?)|(^\s+)|(\s+$)|((\s*?\,+)+\s?$)
ex:
a, b, c
, ,a, b, c,
,a, b, c ,
,,a, b, c, ,,,
, a, b, c, ,
a, b, c
a, b, c ,,
, a, b, c,
, ,a, b, c, ,
, a, b, c ,
,,, a, b, c,,,
,,, ,,,a, b, c,,, ,,,
,,, ,,, a, b, c,,, ,,,
,,,a, b, c ,,,
,,,a, b, c,,,
a, b, c
becomes:
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
a, b, c
Upvotes: 3
Reputation: 994
You can try with this, it worked for me:
if (names.endsWith(",")) {
names = names.substring(0, names.length() - 1);
}
Or you can try with this too:
string = string.replaceAll(", $", "");
Upvotes: 0
Reputation: 420951
To remove the ", "
part which is immediately followed by end of string, you can do:
str = str.replaceAll(", $", "");
This handles the empty list (empty string) gracefully, as opposed to lastIndexOf
/ substring
solutions which requires special treatment of such case.
Example code:
String str = "kushalhs, mayurvm, narendrabz, ";
str = str.replaceAll(", $", "");
System.out.println(str); // prints "kushalhs, mayurvm, narendrabz"
NOTE: Since there has been some comments and suggested edits about the ", $"
part: The expression should match the trailing part that you want to remove.
"a,b,c,"
, use ",$"
."a, b, c, "
, use ", $"
."a , b , c , "
, use " , $"
.I think you get the point.
Upvotes: 167
Reputation: 7492
You can do something like this using 'Java 8'
private static void appendNamesWithComma() {
List<String> namesList = Arrays.asList("test1", "tester2", "testers3", "t4");
System.out.println(namesList.stream()
.collect(Collectors.joining(", ")));
}
Upvotes: 0
Reputation: 430
For more than one commas
String names = "Hello,World,,,";
System.out.println(names.replaceAll("(,)*$", ""));
Output: Hello,World
Upvotes: 3
Reputation: 5336
String str = "kushalhs , mayurvm , narendrabz ,";
System.out.println(str.replaceAll(",([^,]*)$", "$1"));
Upvotes: 1
Reputation: 478
I'm late on this thread but hope it will help to some one.......
String abc = "kushalhs , mayurvm , narendrabz ,";
if(abc.indexOf(",") != -1){
abc = abc.substring(0,abc.length() - 1);
}
Upvotes: 2
Reputation: 2674
Use Guava to normalize all your commas. Split the string up around the commas, throw out the empties, and connect it all back together. Two calls. No loops. Works the first time:
import com.google.common.base.Joiner;
import com.google.common.base.Splitter;
public class TestClass {
Splitter splitter = Splitter.on(',').omitEmptyStrings().trimResults();
Joiner joiner = Joiner.on(',').skipNulls();
public String cleanUpCommas(String string) {
return joiner.join(splitter.split(string));
}
}
public class TestMain {
public static void main(String[] args) {
TestClass testClass = new TestClass();
System.out.println(testClass.cleanUpCommas("a,b,c,d,e"));
System.out.println(testClass.cleanUpCommas("a,b,c,d,e,,,,,"));
System.out.println(testClass.cleanUpCommas("a,b,,, ,c,d, ,,e,,,,,"));
System.out.println(testClass.cleanUpCommas("a,b,c,d, e,,,,,"));
System.out.println(testClass.cleanUpCommas(",,, ,,,,a,b,c,d, e,,,,,"));
}
}
Output:
a,b,c,d,e
a,b,c,d,e
a,b,c,d,e
a,b,c,d,e
a,b,c,d,e
Personally, I hate futzing around with counting limits of substrings and all that nonsense.
Upvotes: 8
Reputation: 16605
This method is in BalusC's StringUtil class. his blog
i use it very often and will trim any string of any value:
/**
* Trim the given string with the given trim value.
* @param string The string to be trimmed.
* @param trim The value to trim the given string off.
* @return The trimmed string.
*/
public static String trim(String string, String trim) {
if (string == null) {
return null;
}
if (trim.length() == 0) {
return string;
}
int start = 0;
int end = string.length();
int length = trim.length();
while (start + length <= end && string.substring(
start, start + length).equals(trim)) {
start += length;
}
while (start + length <= end && string.substring(
end - length, end).equals(trim)) {
end -= length;
}
return string.substring(start, end);
}
ex:
trim("1, 2, 3, ", ", ");
Upvotes: 1
Reputation: 7964
Check if
str.charAt(str.length() -1) == ','
.
Then do
str = str.substring(0, str.length()-1)
Upvotes: 2
Reputation: 383
You can use this:
String abc = "kushalhs , mayurvm , narendrabz ,";
String a = abc.substring(0, abc.lastIndexOf(","));
Upvotes: 13