Reputation: 515
all,
If you use boost pool library, how would you replace the following statement:
MyStruct *someStruct = (MyStruct *) calloc(numOfElements, sizeof(MyStruct));
If it was for one element, I would do:
boost::object_pool<MyStruct> myPool;
MyStruct *someStruct = myPool.malloc();
but since "numOfElements" is a variable, I have the feeling executing a loop of malloc() is not a good idea?
Upvotes: 1
Views: 803
Reputation: 393487
I'd say you need to use pool_alloc
interface:
static pointer allocate(size_type n);
static pointer allocate(size_type n, pointer);
static void deallocate(pointer ptr, size_type n);
Sample from http://www.boost.org/doc/libs/1_47_0/libs/pool/doc/interfaces.html
void func()
{
std::vector<int, boost::pool_allocator<int> > v;
for (int i = 0; i < 10000; ++i)
v.push_back(13);
} // Exiting the function does NOT free the system memory allocated by the pool allocator
// You must call
// boost::singleton_pool<boost::pool_allocator_tag, sizeof(int)>::release_memory()
// in order to force that
Upvotes: 3