CODEWITHSUNDEEP
xamlmaui
Kekhan
Kekhan

Reputation: 3

Conditional label colors in MAUI XAML

I have a StackLayout that binds to a list and I would like to put each item's Text property in a label, with different colors based on the IsSpecial property in the following manner:

<StackLayout BindableLayout.ItemsSource="{Binding Lines}">
    <BindableLayout.ItemTemplate>
        <DataTemplate>
            <Label Text="{Binding Text}" TextColor= "Red if IsSpecial otherwise White"/>
        </DataTemplate>
    </BindableLayout.ItemTemplate>
</StackLayout>

I tried using triggers but I couldn't figure out how to reference the target type properly.

Upvotes: 0

Views: 220

Answers (1)

Julian
Julian

Reputation: 8914

Since you're not showing the model class you're binding to, I'll make an educated guess:

public class Line
{
    public string Text { get; set; }
    public bool IsSpecial { get; set; }
}

or something like (if the values keep changing):

public partial class Line : ObservableObject
{
    [ObservableProperty]
    private string _text;

    [ObservableProperty]
    private bool _isSpecial;
}

Then you can use a DataTrigger like this:

<StackLayout BindableLayout.ItemsSource="{Binding Lines}">
    <BindableLayout.ItemTemplate>
        <DataTemplate x:DataType="model:Line">
            <Label
                Text="{Binding Text}"
                TextColor="White">
                <Label.Triggers>
                    <DataTrigger
                        TargetType="Label"
                        Binding="{Binding IsSpecial}"
                        Value="True">
                        <Setter
                            Property="TextColor"
                            Value="Red" />
                    </DataTrigger>
                </Label.Triggers>
            </Label>
        </DataTemplate>
    </BindableLayout.ItemTemplate>
</StackLayout>

Note that I've also added the x:DataType attribute to enable compiled bindings. That way, the binding expressions get evaluated during compile-time.

Upvotes: 2

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