Reputation: 2875
If I run my program, and When I typed the dimensions of matrix, after I typed the first value of matrix , the console write out: Segmentation fault
For example:
4
3
Segmentation fault Process returned 139(0x8B)
void inMatrix(int n, double **matrix)
{
int j, i;
for (i = 0; i < n; i++)
{
for (j= 0; j < n; j++)
{
scanf("%lf", &matrix[i][j]);
}
}
}
void inVector(double *vektor, int n)
{
int k;
for (k = 0; k < n; k++)
{
scanf("%lf", &vektor[k]);
}
}
int main()
{
int n;
// read dimension of matrix and value
scanf("%d", &n);
//matrix
double** matrix = (double **) calloc(n, sizeof ( double*));
//vector
double* vector = (double *) calloc(n, sizeof ( double));
// read values of matrix
inMatrix(n, matrix);
// read values of vector
inVector(vector, n);
outVector(vector, n);
printf("\n");
return 0;
}
Upvotes: 1
Views: 274
Reputation: 182744
You didn't allocate memory for the elements of the matrix, only for the pointers to the individual lines.
You need something like:
for (i = 0; i < n; i++)
matrix[i] = malloc(n * sizeof(double));
Of course, you must free stuff in the same manner when you're done with it.
for (i = 0; i < n; i++)
free(matrix[i]);
free(matrix);
Upvotes: 5