CODEWITHSUNDEEP
cstring-concatenationstdioconcatenative-language
Lucas Pontes C
Lucas Pontes C

Reputation: 1

Why only the concatenation is not running in this C chalenge?

I am trying to solve this HackerRank challenge:

There are 3 variables already declared: i(integer), d(double), and s(string).

I must declare 3 more variables of the same type as the previous, requesting input with scanf().

Then print sum of i with the second int variable. Then print the sum of d with the second double variable.

Finally, and the only task that I am not able to complete, is to concatenate the s string with the second char variable(string).

The first two tasks were completed smoothly, but the concatenation is not running.

I am getting as output only the first string and 0. (HackerRank 0.)

Here is the code:

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    int i = 4;
    double d = 4.0;
    char s[] = "HackerRank ";
    
    int secondI;
    float secondD;
    char s2[100];

scanf("%d", &secondI);
scanf("%1f", &secondD);
scanf("%s", s2);

printf("%d\n",i + secondI);

printf("%.1f\n", d + secondD);

printf("%s ", s);
printf("%s", s2);



    return 0;
}

```
`

Expected Output
16
8.0
HackerRank is the best place to learn and practice coding!


My Output (stdout)
16
8.0
HackerRank  .0

Upvotes: -3

Views: 74

Answers (1)

pmg
pmg

Reputation: 108978

scanf("%1f", &fvar) reads one character and interprets that single char as a float value which is written into the variable. The rest of the input is then used for the next scanf().

Use scanf("%f", &fvar) with floats ... or scanf("%lf", &dvar) with doubles.

And also check the return value of scanf

if (scanf("%lf", &dvar) != 1) /* error in input */;

Upvotes: 0

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