Reputation: 18198
OK so I fixed my last error with the DIV and all..
OK so at the very top of my javascript
file... I have
$(function() {
var games = new Array(); // games array
});
and then in a new function I have: var gamesLgth = games.length;
but when I run it, I get this: Uncaught ReferenceError: games is not defined
When I weird because I initalized it at the very beginning...
Upvotes: 0
Views: 886
Reputation: 1138
games
is out of scope. You need to store it somewhere such that your other function can access it.
For example, this will make your variable global.
var games;
$(function() {
games = new Array(); // games array
});
$(function() {
var gamesLgth = games.length;
console.log(gamesLgth);
});
Upvotes: 0
Reputation: 136174
By declaring that variable within a function
you have scoped the variable to that function, which means that that variable games
is only available within that function.
$(function() {
var games = new Array(); // games array
...
var gamesLength = games.length; // works fine
});
But this following example will not:
$(function() {
var games = new Array(); // games array
});
$(function() {
var gamesLength = games.length; // won't work - im in a different scope
});
Upvotes: 0