specman : how to generate a list with certain number of specific value?

Question

I have a list of 5 items. I need to generate a list with 3 items equal to 4 and 2 others equal to 2. how to generate it?

my code was :

my_list : list of uint;

gen my_list keeping my_list.count(it==4) = 3;

but i got syntax error for it

Answer 1

I think, you want:

gen my_list keeping { it.is_a_permutation({4;4;4;2;2}) };