Reputation: 747
Still very new to programming...
I have 9x1 Vectors at time t, t+1, t+2 etc.
[10 10 10 10 10 10 10 10 10]'
and matrices. Each matrix is 9x9 and also at time 1, t+1, t+2 etc. =
1 0 0 0 0 0 0 0 0
0 1 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0
0 0 0 1 0 0 0 0 0
0 0 0 0 1 0 0 0 0
0 0 0 0 0 1 0 0 0
0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 0 1
They are 3d matrices and I want to make them 4d in the future.
I want to multiply vector(:,:,t) with the diagonal of matrix at time t and output vector(:,:,t+1).
So in short...
vector t multiplied by diag matrix t = vector t+1
vector t+1 multiplied by diag matrix t+1 = vector t+2
vector t+2 multiplied by diag matrix t+2 = vector t+3 ... and so on.
the diagonal numbers change in each time step but for simplicity sake, let's keep them all at 1 for the moment.
I've tried using diag but it states I have to use a 2D input so only works when I ignore t.
Cheers for your help guys - it's helping me learn a lot. Any hints or solutions will be much appreciated. I know you guys know the simplest and most efficient solutions.
Upvotes: 1
Views: 986
Reputation: 124563
Since the result of each step depends on the previous iteration, it cannot be vectorized. So I would go with @JohnColby's solution.
For what it's worth, here is an example how you would extract the diagonals of a 3D matrix in a vectorized way:
M = reshape(1:3*4*3,[3 4 3]);
[r,c,p] = size(M);
ind = bsxfun(@plus, (1:r+1:r*c)', (0:p-1).*r*c);
M(ind)
Each column of the result corresponds to the diagonal elements from each slice (doesn't have to be square matrix):
>> M
M(:,:,1) =
1 4 7 10
2 5 8 11
3 6 9 12
M(:,:,2) =
13 16 19 22
14 17 20 23
15 18 21 24
M(:,:,3) =
25 28 31 34
26 29 32 35
27 30 33 36
>> M(ind)
ans =
1 13 25
5 17 29
9 21 33
Upvotes: 2
Reputation: 22588
Here you go:
n = 10;
% Make sample data
t = zeros(9,1,n);
t(:,1,1) = 1;
T = repmat(diag(ones(9,1)), [1 1 n]);
% Loop though to fill in t based on previous t and T
for i = 2:n
t(:,1,i) = t(:,1,i-1) .* diag(T(:,:,i-1));
end
Now all of t
should be 1.
Upvotes: 1