anish
anish

Reputation: 7412

Private method in groovy is not private

class A {
    private def sayHello() {
       println "Anish"
    } 
 }

 def a_obj = new A()
 a_obj.sayHello()

output : Anish

Is there any way to protect sayHello() in groovy or am I missing something?

Upvotes: 25

Views: 38971

Answers (5)

hvgotcodes
hvgotcodes

Reputation: 120178

I think its a bug in groovy that is fixed in groovy++.

https://issues.apache.org/jira/browse/GROOVY-1875

Upvotes: 3

solstice333
solstice333

Reputation: 3649

As other posts have mentioned, this may be a bug in Groovy. I've been sticking to a simple convention of prefixing private member names with a leading underscore (similar to Python) to denote that it's private which helps me understand from a client side perspective what I should be calling.

Upvotes: 1

Andrey Adamovich
Andrey Adamovich

Reputation: 20663

There is defect on that in Groovy issue tracking system and that defect is still open.

Upvotes: 24

Jason
Jason

Reputation: 406

You can use closures to achieve a similar effect, basically the same way you would do information hiding with Javascript.

package test

class FunctionTests {

    def privilagedObj = {

        def privVar = 'foo'

        def privateFunc = { x -> println "${privVar} ${x}"}

        return {x -> privateFunc(x) } 
    }

    public static void main(String[] args) {

        def test = new FunctionTests().privilagedObj()

        test('bar')

    }
}

Upvotes: 6

tim_yates
tim_yates

Reputation: 171074

Searching for [groovy] private reveals:

groovy call private method in Java super class

What does 'private' mean in Groovy?

How to define private getter method in Groovy Bean?

It's not clear if it is a bug or by design, but it is going to get looked at again in Groovy 2.0

Upvotes: 10

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