CODEWITHSUNDEEP
ruby
Ishu
Ishu

Reputation: 638

How to make the function accept a block

I am having a class G and my custom function func which i expect to take a block like this:

class G
def func(&block)
return '1' unless block_given?
# More code
end
end

I think that now when i do

G g = new G
g.func {|t| t}

block_given? should return true but its returning false

I hve tried following variants as well to no resort

g.func do |t|
end

Any help would be appreciated.

Upvotes: 2

Views: 352

Answers (2)

Matt
Matt

Reputation: 17629

It's working fine if you correct some minor syntax errors. Note that there is no type declaration for ruby variables and object instantiation is done through an instance method of class Class instead with keyword (like in Java):

class G
  def func(&block)
    return '1' unless block_given?
    block.call
  end
end

g = G.new
g.func { puts 'block was called' }
g.func
# Output:
# irb(main):046:0>g.func { puts 'block was called' }
# block was called
# => nil
# irb(main):047:0>g.func
# => "1"

Upvotes: 4

Dave Newton
Dave Newton

Reputation: 160181

(Adding my output, although Matt beat me to it.)

> class G
>   def func(&block)
>     return '1' unless block_given?
>     # More code
>   end
> end
=> nil 
> g = G.new
=> #<G:0x856e444> 
> g.func { |t| puts "hi" }
=> nil 
> g.func
=> "1"

Upvotes: 0

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