Reputation: 12178
Sorry if this is too basic. I have a csv file where the columns have a header row (v1, v2, etc.). I understand that to extract columns 1 and 2, I have to do: awk -F "," '{print $1 "," $2}' infile.csv > outfile.csv
. But what if I have to extract, say, columns 1 to 10, 20 to 25, and 30, 33? As an addendum, is there any way to extract directly with the header names rather than with column numbers?
Upvotes: 52
Views: 189924
Reputation: 31
You can pass the columns whose values you want to use from outside of AWK.
Eg, using GNU Awk 3.1.7
This Code
echo -e "one,two,three,four,five\none,two,three,four,five" | awk -F"," -v kfields="1_3_5" '
BEGIN {
arrayMax=split(kfields, arrKeys, "_");
}
{
outString="";
for (idx = 1; idx <= arrayMax ; idx++) {
outString=outString$arrKeys[idx];
}
print "outString:"outString;
print "-----------";
}
'
This will output only the columns you specify eg these values mean only output fields 1 and 3 and 5.
kfields="1_3_5"
Eg the output
outString:onethreefive
-----------
outString:onethreefive
-----------
Upvotes: 0
Reputation: 1955
Not using awk but the simplest way I was able to get this done was to just use csvtool. I had other use cases as well to use csvtool and it can handle the quotes or delimiters appropriately if they appear within the column data itself.
csvtool format '%(2)\n' input.csv
csvtool format '%(2),%(3),%(4)\n' input.csv
Replacing 2 with the column number will effectively extract the column data you are looking for.
Upvotes: 1
Reputation: 14910
As mentioned by @Tom, the cut and awk approaches actually don't work for CSVs with quoted strings. An alternative is a module for python that provides the command line tool csvfilter. It works like cut, but properly handles CSV column quoting:
csvfilter -f 1,3,5 in.csv > out.csv
If you have python (and you should), you can install it simply like this:
pip install csvfilter
Please take note that the column indexing in csvfilter starts with 0 (unlike awk, which starts with $1). More info at https://github.com/codeinthehole/csvfilter/
Upvotes: 19
Reputation: 3451
If Perl is an option:
perl -F, -lane 'print join ",",@F[0,1,2,3,4,5,6,7,8,9,19,20,21,22,23,24,29,32]'
-a
autosplits line into @F
fields array. Indices start at 0 (not 1 as in awk)
-F,
field separator is ,
If your CSV file contains commas within quotes, fully fledged CSV parsers such as Perl's Text::CSV_XS
are purpose-built to handle that kind of weirdness.
perl -MText::CSV_XS -lne 'BEGIN{$csv=Text::CSV_XS->new()} if($csv->parse($_)){@f=$csv->fields();print (join ",",@f[0,1,2,3,4,5,6,7,8,9,19,20,21,22,23,24,29,32])}'
I provided more explanation within my answer here: parse csv file using gawk
Upvotes: 2
Reputation: 866
Tabulator is a set of unix command line tools to work with csv files that have header lines. Here is an example to extract columns by name from a file test.csv:
name,sex,house_nr,height,shoe_size
arthur,m,42,181,11.5
berta,f,101,163,8.5
chris,m,1333,175,10
don,m,77,185,12.5
elisa,f,204,166,7
Then tblmap -k name,height test.csv
produces
name,height
arthur,181
berta,163
chris,175
don,185
elisa,166
Upvotes: 2
Reputation: 556
Others have answered your earlier question. For this:
As an addendum, is there any way to extract directly with the header names rather than with column numbers?
I haven't tried it, but you could store each header's index in a hash and then use that hash to get its index later on.
for(i=0;i<$NF;i++){
hash[$i] = i;
}
Then later on, use it:
j = hash["header1"];
print $j;
Upvotes: 3
Reputation: 226199
You can use a for-loop to address a field with $i:
ls -l | awk '{for(i=3 ; i<8 ; i++) {printf("%s\t", $i)} print ""}'
Upvotes: 4
Reputation: 1701
I don't know if it's possible to do ranges in awk. You could do a for loop, but you would have to add handling to filter out the columns you don't want. It's probably easier to do this:
awk -F, '{OFS=",";print $1,$2,$3,$4,$5,$6,$7,$8,$9,$10,$20,$21,$22,$23,$24,$25,$30,$33}' infile.csv > outfile.csv
something else to consider - and this faster and more concise:
cut -d "," -f1-10,20-25,30-33 infile.csv > outfile.csv
As to the second part of your question, I would probably write a script in perl that knows how to handle header rows, parsing the columns names from stdin or a file and then doing the filtering. It's probably a tool I would want to have for other things. I am not sure about doing in a one liner, although I am sure it can be done.
Upvotes: 76
Reputation: 37258
Other languages have short cuts for ranges of field numbers, but not awk, you'll have to write your code as your fear ;-)
awk -F, 'BEGIN {OFS=","} { print $1, $2, $3, $4 ..... $30, $33}' infile.csv > outfile.csv
There is no direct function in awk to use field names as column specifiers.
I hope this helps.
Upvotes: 4