anhtle
anhtle

Reputation: 95

PowerShell - ConvertTo-Json how to get ndjson result

I am trying to split 1 NDJSON file into multiple NDJSON files. I am able to consume and split the file, but the problem is the resulting files are in JSON format. Is it possible to output to NDJSON format or do I have to do some string manipulation?

My input file test.json:

{"PERIOD":"2024004","JRNAL_NO":"38115"}
{"PERIOD":"2024004","JRNAL_NO":"38115"}
{"PERIOD":"2024004","JRNAL_NO":"38115"}
{"PERIOD":"2024004","JRNAL_NO":"38115"}
{"PERIOD":"2024004","JRNAL_NO":"38116"}

My powershell script so far:

$json = (Get-Content C:\Temp\test.json) | ConvertFrom-Json

$jnl_list = $json.JRNAL_NO | select -Unique

ForEach ($jnl in $jnl_list) {
    $Array = $json | Where-Object {$_.JRNAL_NO -eq $jnl}
    $res = ($Array | ConvertTo-Json)    
    $res | Out-File -FilePath .\JNL\$($jnl).json   
}

My current output. Here's the 38115.json file:

[
    {
        "PERIOD":  "2024004",
        "JRNAL_NO":  "38115"
    },
    {
        "PERIOD":  "2024004",
        "JRNAL_NO":  "38115"
    },
    {
        "PERIOD":  "2024004",
        "JRNAL_NO":  "38115"
    },
    {
        "PERIOD":  "2024004",
        "JRNAL_NO":  "38115"
    }
]

I need the output file to be NDJSON, basically the same format as the input file. 38115.json should be:

{"PERIOD":"2024004","JRNAL_NO":"38115"}
{"PERIOD":"2024004","JRNAL_NO":"38115"}
{"PERIOD":"2024004","JRNAL_NO":"38115"}
{"PERIOD":"2024004","JRNAL_NO":"38115"}

38116.json should be:

{"PERIOD":"2024004","JRNAL_NO":"38116"}

Upvotes: 3

Views: 117

Answers (2)

iRon
iRon

Reputation: 23663

To complement the helpful answer from Santiago Squarzon with a presumably more performant solution:
You could also consider to distribute the original lines ("same format as the input file") one-by-one on the fly using the steppable pipeline as in this example where you only use the ConvertTo-Json result to determine the "JRNAL_NO" value:

$Pipeline = @{}
Get-Content .\test.json |
    ForEach-Object -Process {
        $Jnl = ($_ | ConvertFrom-Json).JRNAL_NO
        if (!$Pipeline.Contains($Jnl)) {
            $Pipeline[$Jnl] = { Set-Content .\$Jnl.json }.GetSteppablePipeline()
            $Pipeline[$Jnl].Begin($True)
        }
        $Pipeline[$Jnl].Process($_)
    } -End {
        foreach ($Key in $Pipeline.Keys) { $Pipeline[$Key].End() }
    }

For more details and background, see: Mastering the (steppable) pipeline

Upvotes: 1

Santiago Squarzon
Santiago Squarzon

Reputation: 60045

If I understand correctly what you're looking for, the code my be greatly simplified by using Group-Object.

To get the NDJSON format what you can do is enumerate each object from the group of objects (.Group property) and pass it to ConvertTo-Json -Compress then send that output to your file.

$json = Get-Content C:\Temp\test.json | ConvertFrom-Json
foreach ($group in $json | Group-Object JRNAL_NO) {
    $group.Group |
        ForEach-Object { $_ | ConvertTo-Json -Compress } |
        Set-Content ".\JNL\$($group.Name).json"
}

Code above with the sample data would be creating 2 files:

  • 38115.json
{"PERIOD":"2024004","JRNAL_NO":"38115"}
{"PERIOD":"2024004","JRNAL_NO":"38115"}
{"PERIOD":"2024004","JRNAL_NO":"38115"}
{"PERIOD":"2024004","JRNAL_NO":"38115"}
  • 38116.json
{"PERIOD":"2024004","JRNAL_NO":"38116"}

Upvotes: 4

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