Reputation: 3546
As input, I have a list of gzipped files. As shown here, I use gzstream to handle them. For practical reasons, I want to open each file and record each stream into a vector. It seems pretty straightforward but I don't manage to make it work. Here is the minimal code:
#include <cstdlib>
#include <iostream>
#include <vector>
using namespace std;
#include <gzstream.h>
int main (int argc, char ** argv)
{
size_t i;
vector<string> vInFiles;
vector<igzstream *> vStreams;
string line;
// create the dummy input files
system ("rm -f infile*.gz; for i in {1..2}; do echo \"toto\"${i} | gzip > infile${i}.gz; done");
vInFiles.push_back ("infile1.gz");
vInFiles.push_back ("infile2.gz");
// open each input file
for (i = 0; i < vInFiles.size(); ++i)
{
igzstream inStream;
inStream.open (vInFiles[i].c_str());
if (! inStream.good())
{
cerr << "ERROR: can't open file " << vInFiles[i] << endl;
exit (1);
}
vStreams.push_back (&inStream);
}
// manipulate each input file
for (i = 0; i < vInFiles.size(); ++i)
{
cout << "read first line of file " << vInFiles[i] << endl;
getline (*(vStreams[i]), line);
if (line.empty())
{
cerr << "empty line" << endl;
exit (1);
}
cout << line << endl;
}
// close each input file
for (i = 0; i < vInFiles.size(); ++i)
{
vStreams[i]->close();
}
vStreams.clear();
return 0;
}
This code compiles properly:
$ gcc -Wall test.cpp -lstdc++ -lgzstream -lz
And although it run smoothly, it doesn't read the files properly:
$ ./a.out
read first line of file infile1.gz
empty line
Upvotes: 0
Views: 666
Reputation: 3546
As mentioned in the comments, I would prefer not to use Boost and I only have gcc 4.1.2. Thus, here is the solution using the free store, thanks to the suggestion of Cat Plus Plus:
// open each input file
for (i = 0; i < vInFiles.size(); ++i)
{
igzstream * pt_inStream = new igzstream;
pt_inStream->open (vInFiles[i].c_str());
if (! pt_inStream->good())
{
cerr << "ERROR: can't open file " << vInFiles[i] << endl;
exit (1);
}
vStreams.push_back (pt_inStream);
}
And:
// close each input file
for (i = 0; i < vInFiles.size(); ++i)
{
vStreams[i]->close();
delete vStreams[i];
}
Upvotes: 0
Reputation: 129774
Your stream pointers are invalid after the iteration ends, as the automatic stream object is destroyed then. If you really need that you need to allocate them on the free store (or make igzstream
movable).
// std::vector<boost::shared_ptr<igzstream>> for C++03
std::vector<std::unique_ptr<igzstream>> vStreams;
// ...
for (size_t i = 0; i < vInFiles.size(); ++i) {
// boost::shared_ptr<igzstream> inStream = boost::make_shared<igzstream>();
auto inStream = std::unique_ptr<igzstream>(new igzstream);
inStream->open(...);
// ...
vStreams.push_back(inStream);
}
// ...
Upvotes: 2
Reputation: 33655
This is broken; you store a vector of pointers to streams, but you initialize it with a pointer to a locally scoped automatic instance of the stream (inside the for-loop). Once each iteration of the loop completes, that instance is out of scope, and you have a pointer to some crap.
You then use that crap later, and you get crap out.
Use a smart pointer, e.g.
std::vector<boost::shared_ptr<igzstream> > vStreams;
// to initialize
for (i = 0; i < vInFiles.size(); ++i)
{
boost::shared_ptr<igzstream> inStream(new igzstream(vInFiles[i].c_str());
if (!inStream->good())
{
cerr << "ERROR: can't open file " << vInFiles[i] << endl;
exit (1);
}
vStreams.push_back (inStream); // save the smart pointer
}
Upvotes: 0