Reputation: 2524
The background: I have a function which takes some parameters. I want to have the result of the function for all possible parameter combinations.
A simplified example:
f <- function(x, y) { return paste(x, y, sep=",")}
colors = c("red", "green", "blue")
days = c("Monday", "Tuesday")
I want my result to look like
color day f
[1,] "red" "Monday" "red,Monday"
[2,] "red" "Tuesday" "red,Tuesday"
[3,] "green" "Monday" "green,Monday"
[4,] "green" "Tuesday" "green,Tuesday"
[5,] "blue" "Monday" "blue,Monday"
[6,] "blue" "Tuesday" "blue,Tuesday"
My idea is to create a matrix with the columns color
and day
, fill it using the existing vectors colors
and days
, initialize an empty column for the results, then use a loop to call f once per matrix row and write the result into the last column. But I don't know how to easily generate the matrix from the colors
and days
vector. I tried searching for it, but all results I got were for the combn
function, which does something different.
In this simplified case, the colors
and days
are factors, but in my real example, this is not the case. Some of the parameters to the function are integers, so my real vector may look more like 1, 2, 3
and the function will require that it is passed to it as numeric. So please no solutions which rely on factor levels, if they can't somehow be used to work with integers.
Upvotes: 9
Views: 7855
Reputation: 173697
I think you just want expand.grid
:
> colors = c("red", "green", "blue")
> days = c("Monday", "Tuesday")
> expand.grid(colors,days)
Var1 Var2
1 red Monday
2 green Monday
3 blue Monday
4 red Tuesday
5 green Tuesday
6 blue Tuesday
And, if you want to specify the column names in the same line:
> expand.grid(color = colors, day = days)
color day
1 red Monday
2 green Monday
3 blue Monday
4 red Tuesday
5 green Tuesday
6 blue Tuesday
Upvotes: 23