Reputation: 1904
I'm still confused about priority queue in STL. Here is the objective I wanna achieve, say: I have a structure called Record, which contains a string word and a int counter. For example: I have many records of these (in the sample program, only 5), now I want to keep top N records(in sample, 3).
I know now that I could overload operator < in Record, and put all records in a vector, and then initialize the priority_queue like:
priority_queue< Record, vector<Record>, less<Record> > myQ (myVec.begin(),myVec.end());
However, as I understood, it's not easy to control the size of vector myVec because it's not sorted as I wanted.
I really don't understand why the following can not work:
struct Record
{
string word;
int count;
Record(string _word, int _count): word(_word), count(_count) { };
/*
bool operator<(const Record& rr)
{
return this->count>rr.count;
}
*/
bool operator() (const Record& lhs, const Record& rhs)
{
return lhs.count>rhs.count;
}
};
void test_minHeap()
{
priority_queue<Record> myQ;
Record arr_rd[] = {Record("William", 8),
Record("Helen", 4),
Record("Peter", 81),
Record("Jack", 33),
Record("Jeff", 64)};
for(int i = 0; i < 5; i++)
{
if(myQ.size() < 3)
{
myQ.push(arr_rd[i]);
}
else
{
if(myQ.top().count > arr_rd[i].count)
continue;
else
{
myQ.pop();
myQ.push(arr_rd[i]);
}
}
}
while(!myQ.empty())
{
cout << myQ.top().word << "--" << myQ.top().count << endl;
myQ.pop();
}
}
Edit: Thanks for your input, now I got it working.However, I prefer if someone could explain why the first version of operator< overload works, the second one (commented out one) won't work and has a long list of compiler errors.
friend bool operator< (const Record& lhs, const Record& rhs)
{
return lhs.count>rhs.count;
}
/*
bool operator<(const Record& rRecord)
{
return this->count>rRecord.count;
}
*/
Upvotes: 5
Views: 23403
Reputation: 473447
std::priority_queue
cannot magically know how to sort the elements. You must tell it how to do so. The way to do that is to give priority_queue
a functor type which, when called with two objects, returns whether the first argument is "less than" the second, however you want to define that. This functor is a template parameter to the priority_queue
.
The default parameter is std::less<type>
, which requires that type
(what you're putting in the queue) has an overloaded operator<
. If it doesn't, then you either have to provide one or you have to provide a proper comparison functor.
For example:
struct Comparator
{
bool operator()(const Record& lhs, const Record& rhs)
{
return lhs.count>rhs.count;
}
};
std::priority_queue<Record, std::vector<Record>, Comparator> myQ;
The reason that doesn't work with just an overload on Record
is because you didn't tell the priority_queue
that it was the comparison. Also, the type used for comparison needs to be default constructable, so that the priority_queue
can create and destroy the objects at will.
Though to be honest, I don't know why you don't just stick them in a std::set
if you want to sort them. Or just run std::sort
on the std::vector
of items.
Upvotes: 12
Reputation: 254461
Your code does work, with two small changes:
Record::operator<()
, since that's needed by the priority queue's default comparator.bool operator<(const Record &) const
(note the extra const
), since the priority queue has to compare using references to const
objects. Alternatively, declare it as a free function, outside the class definition:
bool operator<(const Record &l, const Record &r) {return l.count > r.count;}
or define your own functor, and provide that as the appropriate template argument:
struct CompareRecords
{
bool operator()(const Record &l, const Record &r) {return l.count > r.count;}
};
typedef priority_queue<Record, vector<Record>, CompareRecords> RecordQueue;
Upvotes: 4