CODEWITHSUNDEEP
jsonxslt-3.0altovaxmlspy
chris457
chris457

Reputation: 74

How to pass the "xsl:initial-template" in Altova XMLSpy 2024

I want to process JSON by XSLT 3.0. I am using Altova XMLSpy 2024. I can't seem to find how to initiate the processing without at least one dummy XML file and a <xsl:template match="/">.

  1. Where do I pass the name of my initial template in XMLSpy?

  2. And how can I make a <xsl:template name="xsl:initial-template"> picked up by the processor inside XMLSpy without requiring a dummy XML input file?

@MartinHonnen was so kind as to provide an answer to an earlier question of mine which included a template <xsl:template match="/" name="xsl:initial-template"> but I could not get it to work in XMLSpy without a dummy XML input file: XSLT 3.0 Processing JSON: improving a functions-based solution I would like to use that example.

I need to use XMLSpy so any suggestions for other processors are sadly of no use to me. Thank you. I have also searched the Altova online help but it was fruitless. Any link describing how to do it in XMLSpy is very much apprechiated.

Upvotes: 0

Views: 32

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